已采纳回答 / 慕哥2041944
这个涉及到变量的作用域和临时变量的生命周期的问题了。程序执行时自上而下执行的sum=0.0 ##这里时声明一个临时变量sum，并给他赋值0.0， sum=sum+5，时把新值赋值给sum，所以此时的sum跟一开始的sum不一样了。类似，x=1, 而后我重新对x进行复制x=5, 此时x的值为5.
2021-01-12
num=0
sum=0
while num <= 1000:
num = num + 1
if num % 2 == 1:
continue
sum = sum + num
print(sum)
sum=0
while num <= 1000:
num = num + 1
if num % 2 == 1:
continue
sum = sum + num
print(sum)
2021-01-12
num=0
sum=0
while True:
if num>1000:
break
sum=sum+num
num=num+2
print(sum)
sum=0
while True:
if num>1000:
break
sum=sum+num
num=num+2
print(sum)
2021-01-12
T = (1, 'CH', [3, 4])
T = list(T)
T[2] = tuple(list(T[2]))
print(tuple(T))
T = list(T)
T[2] = tuple(list(T[2]))
print(tuple(T))
2021-01-12
L=['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
print(L)
L.append('Gen')
L.append('Zero')
L.insert(6,'Phoebe')
print(L)
2021-01-11
L=['Alice',66,'Bob',True,'False',100]
i=0
for item in L:
if i%2==0:
print(item)
i=i+1
i=0
for item in L:
if i%2==0:
print(item)
i=i+1
2021-01-11
# coding=utf-8
def sub_sum(li):
ji_sum = 0
ou_sum = 0
for i in range(len(li)):
if (i%2) == 1:
ou_sum += li[i]
else:
ji_sum += li[i]
return ou_sum,ji_sum
li = [1,2,3,4,5,6,7,8]
[ou,ji] = sub_sum(li)
print(ou,ji)
def sub_sum(li):
ji_sum = 0
ou_sum = 0
for i in range(len(li)):
if (i%2) == 1:
ou_sum += li[i]
else:
ji_sum += li[i]
return ou_sum,ji_sum
li = [1,2,3,4,5,6,7,8]
[ou,ji] = sub_sum(li)
print(ou,ji)
2021-01-11
# Enter a code
s1='ABC'
s2='123'
s3='xyz'
for x in s1+s2+s3:
for y in s1+s2+s3:
for z in s1+s2+s3:
print(x+y+z)
s1='ABC'
s2='123'
s3='xyz'
for x in s1+s2+s3:
for y in s1+s2+s3:
for z in s1+s2+s3:
print(x+y+z)
2021-01-10
# Enter a code
s1='ABC'
s2='123'
s3='xyz'
for x in s1,s2,s3:
for y in s1,s2,s3:
for z in s1,s2,s3:
print(x+y+z)
s1='ABC'
s2='123'
s3='xyz'
for x in s1,s2,s3:
for y in s1,s2,s3:
for z in s1,s2,s3:
print(x+y+z)
2021-01-10
已采纳回答 / 粗实而夜雨
首先你得理解%的含义，这是取模（取余数）操作，1%2=2；用 num % 2 != 0作为条件也就是余数等于1，题目中要求的是取偶数位置的数据，而列表list的第一位是0，第二个位置是1，以此类推。
2021-01-10