d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
name = 'Alice'
if name in d.keys():
d.pop(name)
print(d)
else:
print('{} not in d'.format(name))
# 当key不存在的时候，但是名字存在呀，所以把名字找出来定义了，然后删除名字，再输入，就可以得到了
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
name = 'Alice'
if name in d.keys():
d.pop(name)
print(d)
else:
print('{} not in d'.format(name))
# 当key不存在的时候，但是名字存在呀，所以把名字找出来定义了，然后删除名字，再输入，就可以得到了
2021-01-17
d = {
'Alice': [45],
'Bob': [60],
'Candy': [75],
}
d['Alice'] = [50,61,77]
d['Bob'] = [80,61,66]
d['Candy'] = [88,75,90]
print(d)
'Alice': [45],
'Bob': [60],
'Candy': [75],
}
d['Alice'] = [50,61,77]
d['Bob'] = [80,61,66]
d['Candy'] = [88,75,90]
print(d)
2021-01-17
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
}
print(d.get('Alice'))
print(d.get('Bob'))
print(d.get('Candy'))
print(d.get('David'))
print(d.get('Mimi'))
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
}
print(d.get('Alice'))
print(d.get('Bob'))
print(d.get('Candy'))
print(d.get('David'))
print(d.get('Mimi'))
2021-01-16
d= {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
'Gaven': 86
}
print(d)
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49,
'Gaven': 86
}
print(d)
2021-01-16
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
print(T)
运行成功
(3, (3,), 'ab', (1,), (1, 2, 3, 4, 5))
结果是5个
print(T)
运行成功
(3, (3,), 'ab', (1,), (1, 2, 3, 4, 5))
结果是5个
2021-01-15
T = (100, 69, 29, 100, 72, 99, 98, 100, 75, 100, 100,42,88,100)
print(T.count(100))
print(T.count(100))
2021-01-14
T = ('0', '1', '2', '3', '4','5','6','7','8','9')
print(T)
L=list(T)
print(L)
print(T)
L=list(T)
print(L)
2021-01-14
L=['Alice','Bob','Candy','David','Ellena']
L[0]='Ellena'
L[1]='Alice'
L[2]='Candy'
L[3]='David'
L[4]='Bob'
print(L)
L[0]='Ellena'
L[1]='Alice'
L[2]='Candy'
L[3]='David'
L[4]='Bob'
print(L)
2021-01-14
L=['Alice','Bob','Candy','David','Ellena']
L.pop(2)
L.pop(2)
print(L)
L.pop(2)
L.pop(2)
print(L)
2021-01-14