>>> s1='这是一句中英文混合的Python字符串:Hello World!'
>>> print(s1)
这是一句中英文混合的Python字符串:Hello World!
>>> print(s1)
这是一句中英文混合的Python字符串:Hello World!
2021-01-07
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for a in T:
print(type(a))
结果：
<class 'int'>
<class 'tuple'>
<class 'str'>
<class 'tuple'>
<class 'tuple'>
所以是3个
for a in T:
print(type(a))
结果：
<class 'int'>
<class 'tuple'>
<class 'str'>
<class 'tuple'>
<class 'tuple'>
所以是3个
2021-01-07
>>> template='Life is short,you need {}'
>>> a='Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
或者
>>> template='Life is short,{}'
>>> a='you need Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
>>> a='Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
或者
>>> template='Life is short,{}'
>>> a='you need Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
2021-01-07
>>> template='Life is short,you need {}'
>>> a='Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
或者
>>> template='Life is short,{}'
>>> a='you need Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
>>> a='Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
或者
>>> template='Life is short,{}'
>>> a='you need Python'
>>> result=template.format(a)
>>> print(result)
Life is short,you need Python
2021-01-07
可以参考一下我的：
num=0
sum=0
while num<=1000:
if num%2<>0:
num=num+1
continue
sum=sum+num
num=num+1
print(sum,num)
num=0
sum=0
while num<=1000:
if num%2<>0:
num=num+1
continue
sum=sum+num
num=num+1
print(sum,num)
2021-01-06
d = {
'Alice': [45],
'Bob': [60],
'Candy': [75],
};
socre_a=[50,61,66];
socre_b=[80,61,66];
socre_c=[88,75,90];
num=0;
while num<3:
d['Alice'].append(socre_a[num]);
d['Bob'].append(socre_b[num]);
d['Candy'].append(socre_c[num]);
num+=1;
print(d);
'Alice': [45],
'Bob': [60],
'Candy': [75],
};
socre_a=[50,61,66];
socre_b=[80,61,66];
socre_c=[88,75,90];
num=0;
while num<3:
d['Alice'].append(socre_a[num]);
d['Bob'].append(socre_b[num]);
d['Candy'].append(socre_c[num]);
num+=1;
print(d);
2021-01-06
最赞回答 / 慕侠0184542
>>> L = [75, 92, 59, 68, 99]>>> sum = 0>>> for l in L:... sum = sum +l... >>> print( sum / 5)78.6for和print应该这样对齐。
2021-01-06
>>> s='special string:\',",\\,\\\,\\n,\\t'
>>> print(s)
special string:',",\,\\,\n,\t
>>> print(s)
special string:',",\,\\,\n,\t
2021-01-05
#coding:UTF-8
num = 1
a=0
sum=0
while True:
if a>1000:
break
if a%2==1:
sum=sum+0
else:
sum=sum+a
a=a+2
print(sum)
num = 1
a=0
sum=0
while True:
if a>1000:
break
if a%2==1:
sum=sum+0
else:
sum=sum+a
a=a+2
print(sum)
2021-01-05
最赞回答 / 粗实而夜雨
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))for i in T: print(i)结果是这样的：
3 (3,) ab (1,) (1, 2, 3, 4, 5)这里面包含了三个元组，但是最外面的大的（它本身）也算一个的吧，所以一共应该是4个元组
2021-01-05