最赞回答 / 幕布斯4328471
num = 2sum = 0while True: if num >= 1000: break sum = sum + num num = num + 2print(sum)小写t改成大写t就可以了。
2020-11-06
# Enter a code
score = 16
if score > 18:
print('adult')
else:
print('teenager')
score = 16
if score > 18:
print('adult')
else:
print('teenager')
2020-11-05
ge = 19
if age > 18:
print('adult',age)
print ('ddq = {}'.format (age))
print ('adult')
if age > 18:
print('adult',age)
print ('ddq = {}'.format (age))
print ('adult')
2020-11-05
template = 'life is {0}, you need {1},'
result = template.format('short', 'python')
print(result)
template = 'life is {s}, you need {p}, '
s = 'short'
p = 'python'
result = template.format(s ='short', p = 'python')
print (result)
result = template.format('short', 'python')
print(result)
template = 'life is {s}, you need {p}, '
s = 'short'
p = 'python'
result = template.format(s ='short', p = 'python')
print (result)
2020-11-04
# Enter a code
template = 'life is short, {}'
Y = 'you need python'
result = template.format(Y)
print(result)
template = 'life is short, {}'
Y = 'you need python'
result = template.format(Y)
print(result)
2020-11-04
#for循环序写法
def sum100(s):
num = 0
for a in range(1,s+1):
num+= a
return num
print (sum100(5))
def sum100(s):
num = 0
for a in range(1,s+1):
num+= a
return num
print (sum100(5))
2020-11-04
# Enter a code
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
num = 0
for t in T:
if isinstance(t,tuple):
num += 1
print(num)
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
num = 0
for t in T:
if isinstance(t,tuple):
num += 1
print(num)
2020-11-04
T = (100, 69, 29, 100, 72, 99, 98, 100, 75, 100, 100, 42, 88, 100)
print(T.count(100))
print(T.count(100))
2020-11-04
已采纳回答 / 因为是库里呀
我给你举个例子 最后一次 当a= 1000，满足循环，仍进行一遍语句，最后一句是a=a+2,也就是这时候a= 1000+2=1002当a=1002，不满足a <= 1000，这时候你print(a)当然就是1002咯
2020-11-03