python进阶_技术问答

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python进阶

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慕移动214607

import math

def is_sqr(x):
a = int(math.sqrt(x))
return a*a == x

print filter(is_sqr, range(1, 101))

0 2-6 python中filter()函数

2019-08-14

慕移动214607

def prod(x, y):
return x*y

print reduce(prod, [2, 4, 5, 7, 12])

0 2-5 python中reduce()函数

2019-08-14

慕移动214607

def format_name(s):
return s[0].upper()+s[1:].lower()

print map(format_name, ['adam', 'LISA', 'barT'])

1 2-4 python中map()函数

2019-08-14

小白奈斯

def format_name(s):
return s. title()
print(list(map(format_name,['adma'],['LISA'],['Bart'])))

2 2-4 python中map()函数

2019-08-12

Janyn

开根号函数 math.sqrt()

0 2-3 python把函数作为参数

2019-08-09

盐明

import math

def is_sqr(x):

return (math.sqrt(x)%1 ==0)

print filter(is_sqr, range(1, 101))

返回平方根后除以1余数为0的值也可以达到目的

0 2-6 python中filter()函数

2019-08-08

慕工程8545273

在vb.net和C#里要写成
(Must) Overrides proterty

0 5-4 python中多态

2019-08-08

慕工程8545273

高阶函数有点像委托

0 2-2 python中高阶函数

2019-08-05

weixin_慕斯2439626

用lambda表达式，强制保留局部值
def count():
fs = []
for i in range(1, 4):
a = i * i
fs.append(lambda a=a: a)
return fs

f1, f2, f3 = count()
print f1(), f2(), f3()

0 2-9 python中闭包

2019-08-05

慕标6607929

class Fib(object):
def __call__(self,num):
self.num=L[:num]
return self.num
L=[0,1, 1, 2, 3, 5, 8, 13, 21, 34, 55]

f = Fib()
print f(10)

0 6-9 python中 __call__

2019-08-04

慕标6607929

class Fib(object):

def __init__(self, num):
self.num=L[:num]

def __str__(self):
return str(self.num)

def __len__(self):
return len(self.num)

L=[0,1, 1, 2, 3, 5, 8, 13, 21, 34, 55]
f = Fib(10)
print f
print len(f)

0 6-4 python中 __len__

2019-08-04

Atheny

这篇博文讲的很透彻
https://blog.csdn.net/weixin_41656968/article/details/80286238

1 6-7 python中 @property

2019-08-02

最爱喝酸奶

class Person(object):
__count = 0
def __init__(self, name):
Person.__count += 1
self.name = name
print Person.__count

p1 = Person('Bob')
p2 = Person('Alice')

try:
print Person.__count
except AttributeError:
print 'attributeError'

0 4-7 python中类属性和实例属性名字冲突怎么办

2019-08-01