在该任务中,因为Python把0、空字符串和None看成False,其他数值和非空字符串都看成True,所以变量a是True,变量b是False,按照短路计算2规则可知第一个打印结果为('hello','python'),第二个打印结果为('hello','world')。
2024-08-01
p=int(input("Put an even number \n I will give you the sum of this even columns from 0 to it"))
s=0
n=0
while n<=p:
n=n+1
if n%2!=0:
continue
s=s+n
print(s)
s=0
n=0
while n<=p:
n=n+1
if n%2!=0:
continue
s=s+n
print(s)
2024-07-26
#coding:utf-8
# Enter a code
T_1 = (1, 'CH', [3, 4]) #--> (1, 'CH', (3, 4))
#要把可变的tuple变为不可变的tuple,就是要把tuple中类型为list的元素修改为tuple
#因此:我们就要先把可变的tuple修改为list,记作List
List = list(T_1)
#再把List中的list修改为tuple
List[2] = tuple(List[2])
#最后再把List修改回tuple
T_3 = tuple(List)
#输出(1, 'CH', (3, 4))
print(T_3)
# Enter a code
T_1 = (1, 'CH', [3, 4]) #--> (1, 'CH', (3, 4))
#要把可变的tuple变为不可变的tuple,就是要把tuple中类型为list的元素修改为tuple
#因此:我们就要先把可变的tuple修改为list,记作List
List = list(T_1)
#再把List中的list修改为tuple
List[2] = tuple(List[2])
#最后再把List修改回tuple
T_3 = tuple(List)
#输出(1, 'CH', (3, 4))
print(T_3)
2024-07-10
#请分别使用循环和递归的形式定义函数,求出1~100的和
def tSum(n):
i = 0
result = 0
while i <= n:
result += i
i += 1
return result
print(tSum(100))
def fSum(n):
if n == 1:
return 1
return fSum(n-1) + n
print(fSum(100))
def tSum(n):
i = 0
result = 0
while i <= n:
result += i
i += 1
return result
print(tSum(100))
def fSum(n):
if n == 1:
return 1
return fSum(n-1) + n
print(fSum(100))
2024-07-06
#已知两个集合s1、s2,请判断两个集合是否有重合,如果有,请把重合的元素打印出来。
s1 = set([1, 2, 3, 8, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
#判断是否有重合
hasDuplicate = s1.isdisjoint(s2)
if hasDuplicate == False: #有重合
#取得重合元素
dup = s1.intersection(s2)
print(dup)
s1 = set([1, 2, 3, 8, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
#判断是否有重合
hasDuplicate = s1.isdisjoint(s2)
if hasDuplicate == False: #有重合
#取得重合元素
dup = s1.intersection(s2)
print(dup)
2024-07-06
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name_set = set(names)
#全部设置为大写
names_Upper = [word.upper() for word in names]
name = 'bob'
desprition = "是班里同学"
if name.upper() in names_Upper:
print(name+desprition)
else:
print('查无此人')
name_set = set(names)
#全部设置为大写
names_Upper = [word.upper() for word in names]
name = 'bob'
desprition = "是班里同学"
if name.upper() in names_Upper:
print(name+desprition)
else:
print('查无此人')
2024-07-06
d = {
'Alice': [45],
'Bob': [60],
'Candy': [75],
}
dNew = {
'Alice': [50,61,66],
'Bob': [80,61,66],
'Candy': [88,75,90],
}
Name_L = ['Alice','Bob','Candy']
#循环L,逐个增加
for l in Name_L:
for s in range(0,3,1):
dnew_s = dNew[l][s]
d[l].append(dnew_s)
print(d)
'Alice': [45],
'Bob': [60],
'Candy': [75],
}
dNew = {
'Alice': [50,61,66],
'Bob': [80,61,66],
'Candy': [88,75,90],
}
Name_L = ['Alice','Bob','Candy']
#循环L,逐个增加
for l in Name_L:
for s in range(0,3,1):
dnew_s = dNew[l][s]
d[l].append(dnew_s)
print(d)
2024-07-06