In [13]:

def vcb(**c):
namess = c['names']
genderss = c['genders']
agess = c['ages']
index = 0
for name in namess:
gender = genderss[index]
age = agess[index]
index += 1
print(name + ' is a ' + gender + ' of '+ age)
#输入时注意列表里面的元素都为字符串即可

def vcb(**c):
namess = c['names']
genderss = c['genders']
agess = c['ages']
index = 0
for name in namess:
gender = genderss[index]
age = agess[index]
index += 1
print(name + ' is a ' + gender + ' of '+ age)
#输入时注意列表里面的元素都为字符串即可
2022-02-03
In [9]:

def vcb(names,genders,ages):
index = 0
for name in names:
gender = genders[index]
age = ages[index]
index += 1
print(name + ' is a ' + gender + ' of '+ age)
#输入时注意列表里面的元素都为字符串即可

def vcb(names,genders,ages):
index = 0
for name in names:
gender = genders[index]
age = ages[index]
index += 1
print(name + ' is a ' + gender + ' of '+ age)
#输入时注意列表里面的元素都为字符串即可
2022-02-03
def hancan(x):
listhe = 0
tuplehe = 1
if isinstance(x,list):
for i in x:
listhe += i
return listhe
elif isinstance(x,tuple):
for j in x:
tuplehe *= j
return tuplehe
else:
return '数据类型有误'
listhe = 0
tuplehe = 1
if isinstance(x,list):
for i in x:
listhe += i
return listhe
elif isinstance(x,tuple):
for j in x:
tuplehe *= j
return tuplehe
else:
return '数据类型有误'
2022-02-03
或运算下
a是字符串,判断为ture 返回a
b是空字符串判断为false,结果取决于world,返回world
输出hello Python
hello world
a是字符串,判断为ture 返回a
b是空字符串判断为false,结果取决于world,返回world
输出hello Python
hello world
2022-02-02
In [45]:

a =[1,2,3,4,5,6,7,8,9,10]
b =set([1,3,5,7,9,11])
for j in a:
if j in b:
b.remove(j)
else:
b.add(j)
continue
print(b)

a =[1,2,3,4,5,6,7,8,9,10]
b =set([1,3,5,7,9,11])
for j in a:
if j in b:
b.remove(j)
else:
b.add(j)
continue
print(b)
2022-02-02
In [17]:

for i in q:
j = i.lower()
q.add(j)
print(q)
if j in q:
break

for i in q:
j = i.lower()
q.add(j)
print(q)
if j in q:
break
2022-02-02
列表合并函数 exterd
a =['Ab','Ac']
b =lower(a)
a.exterd(b)
print(a)
==>['Ab','Ac','ab','ac']
a =['Ab','Ac']
b =lower(a)
a.exterd(b)
print(a)
==>['Ab','Ac','ab','ac']
2022-02-01
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for i in T:
print(i)
for i in T:
print(i)
2022-01-26
其实这就是集合的差集运算,个人觉得下列代码更为优雅
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
S = set([1, 3, 5, 7, 9, 11])
L2S = set(L)
res = L2S - S
print(res)
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
S = set([1, 3, 5, 7, 9, 11])
L2S = set(L)
res = L2S - S
print(res)
2022-01-24
# Enter a code
def square_of_sum(L):
result=0
for num in L:
result=result+num*num
return result
l=[1,2,3,4]
print(square_of_sum(l))
def square_of_sum(L):
result=0
for num in L:
result=result+num*num
return result
l=[1,2,3,4]
print(square_of_sum(l))
2022-01-20
# Enter a code
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
print(s1.intersection(s2))
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
print(s1.intersection(s2))
2022-01-19
# Enter a code
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
S = set([1, 3, 5, 7, 9, 11])
for i in L:
if i in S:
S.remove(i)
print(S)
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
S = set([1, 3, 5, 7, 9, 11])
for i in L:
if i in S:
S.remove(i)
print(S)
2022-01-19
# coding=utf-8
s1=set()
s2=set()
names=['Jenny', 'Ellena', 'Alice', 'Candy', 'David', 'Hally', 'Bob', 'Isen', 'Karl']
for name in names:
s1.add(name)
names_set=set(s1)
print(s1)
s2.update(names)
print(s2)
s1=set()
s2=set()
names=['Jenny', 'Ellena', 'Alice', 'Candy', 'David', 'Hally', 'Bob', 'Isen', 'Karl']
for name in names:
s1.add(name)
names_set=set(s1)
print(s1)
s2.update(names)
print(s2)
2022-01-19