print(r'''"To be,or not to be":that is the question.
Whether it's nobler in the mind to suffer.''')
Whether it's nobler in the mind to suffer.''')
2022-02-14
注意缩进哟
s1=set([1,2,4,5,6])
s2=set([1,2,3,4,5,6,7,8,])
if s1.isdisjoint(s2)==False:
for x in s1:
if x in s2:
print(x,end=' ')
s1=set([1,2,4,5,6])
s2=set([1,2,3,4,5,6,7,8,])
if s1.isdisjoint(s2)==False:
for x in s1:
if x in s2:
print(x,end=' ')
2022-02-11
def my_work(**kwargs):
for j , i in enumerate(kwargs.get('names')):
print('姓名:{},性别:{},年龄:{}'.format(i,kwargs.get('gender')[j],kwargs.get('age')[j]))
return
my_work(names=['熊猫','大象','狗熊'],gender=['男','女','男'],age=[18,28,33])
for j , i in enumerate(kwargs.get('names')):
print('姓名:{},性别:{},年龄:{}'.format(i,kwargs.get('gender')[j],kwargs.get('age')[j]))
return
my_work(names=['熊猫','大象','狗熊'],gender=['男','女','男'],age=[18,28,33])
2022-02-11
def square_of_sum(L):
L1=[]
for i in L:
L1.extend([i*i])
return sum(L1)
print(square_of_sum([1, 2, 3, 4, 5]))
L1=[]
for i in L:
L1.extend([i*i])
return sum(L1)
print(square_of_sum([1, 2, 3, 4, 5]))
2022-02-09
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
new_names=[]
for i in names:
name_lower=i.lower()
new_names.append(name_lower)
print(new_names)
new_names=[]
for i in names:
name_lower=i.lower()
new_names.append(name_lower)
print(new_names)
2022-02-09
d = dict()
d['Alice'] = [50, 61, 66]
d['Bob'] = [80, 61, 66]
d['Candy'] = [88, 75, 90]
d['Alice'] = [50, 61, 66]
d['Bob'] = [80, 61, 66]
d['Candy'] = [88, 75, 90]
2022-02-09
num = 2
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print(sum) # ==> 250500
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print(sum) # ==> 250500
2022-02-08
# coding: utf-8
s1 = '这是一句中英文混合的{}字符串:{}'
python = 'Python'
hello = 'Hello World!'
result = s1.format(python , hello)
print(result)
s1 = '这是一句中英文混合的{}字符串:{}'
python = 'Python'
hello = 'Hello World!'
result = s1.format(python , hello)
print(result)
2022-02-07
t = (100, 69, 29, 100, 72, 99, 98, 100, 75, 100, 100,42, 88, 100)
print(t.count(100))
print(t.count(100))
2022-02-07