s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if not s1.isdisjoint(s2):
for i in s1:
if i in s2:
print(i)
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
if not s1.isdisjoint(s2):
for i in s1:
if i in s2:
print(i)
2020-09-23
重合的值不是12345嘛,应该是这样的呀,求童鞋指点
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
flag = s1.isdisjoint(s2)
if not flag:
for item in s2:
if item in s1:
print(item)
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
flag = s1.isdisjoint(s2)
if not flag:
for item in s2:
if item in s1:
print(item)
2020-09-22
# Enter a code
def info(*args):
for i in args:
print('name: {}, gender: {}, age: {}'.format(i[0],i[1],i[2]))
info([1,2,3],[11,1,1],[12,3,4])
#easier?
def info(*args):
for i in args:
print('name: {}, gender: {}, age: {}'.format(i[0],i[1],i[2]))
info([1,2,3],[11,1,1],[12,3,4])
#easier?
2020-09-22
# 递归
def my_sumB(n):
sum = 0
if n == 1:
sum = n
else:
sum = n + my_sumB(n - 1)
return sum
#循环
def your_sumB(n):
s=0
for i in range(1,n+1):
s+=i
return s
def my_sumB(n):
sum = 0
if n == 1:
sum = n
else:
sum = n + my_sumB(n - 1)
return sum
#循环
def your_sumB(n):
s=0
for i in range(1,n+1):
s+=i
return s
2020-09-22
# coding=utf-8
def sub_sum(mylist):
s1 = s2 = 0
for i in mylist:
if i % 2 == 0:
s2 += i
else:
s1 += i
return s1, s2
list1 = [1, 2, 3]
print(sub_sum(list1))
def sub_sum(mylist):
s1 = s2 = 0
for i in mylist:
if i % 2 == 0:
s2 += i
else:
s1 += i
return s1, s2
list1 = [1, 2, 3]
print(sub_sum(list1))
2020-09-22
# Enter a code
def square_of_sum(mylist):
s = 0
for i in mylist:
s += i**2
return s
mylist = [1, 2, 3, 4, 5]
print(square_of_sum(mylist))
def square_of_sum(mylist):
s = 0
for i in mylist:
s += i**2
return s
mylist = [1, 2, 3, 4, 5]
print(square_of_sum(mylist))
2020-09-22