如何确保 addRating（） 方法的输入介于 1 和 5 之间？

Question

请参阅下面粗体部分。如果有人能帮助我，我将不胜感激。 如何确保 addRating（） 方法的输入介于 1 和 5 之间？也许有某种方法可以阻止代码继续/处理平均评分，如果其中一个评分低于 1 且高于 5。class Media {  constructor(title) {    this._title = title;    this._isCheckedOut = false;    this._ratings = [];  }    get title() {    return this._title;  }  get isCheckedOut() {    return this._isCheckedOut;  }  get ratings() {    return this._ratings;  }  set isCheckedOut(status) {    this._isCheckedOut = status;  }  toggleCheckOutStatus() {    this.isCheckedOut = !this.isCheckedOut;  }  getAverageRating() {    let ratingsSum = this.ratings.reduce((accumulator, currentRating) =>    accumulator + currentRating);    return ratingsSum/this.ratings.length;  }  // Here is the mentioned function  // look inside addRating()  addRating(newRating) {    if (newRating < 1 || newRating > 5) {      console.log("Invalid Input. Please enter an integer between 1-   5.");      } else {      this.ratings.push(newRating);    }  }}class Book extends Media {  constructor(author, title, pages) {    super(title);    this._author = author;    this._pages = pages;  }  get author() {    return this._author;  }   get pages() {    return this._pages;  }}class Movie extends Media {  constructor(director, title, runTime) {    super(title);    this._director = director;    this._runTime = runTime;  }  get director() {    return this._director;  }  get runTime() {    return this._runTime;  }}const historyOfEverything = new Book('Bill Bryson', 'A Short History of Nearly Everything', 544);historyOfEverything.toggleCheckOutStatus();console.log(historyOfEverything.isCheckedOut);historyOfEverything.addRating(4);historyOfEverything.addRating(5);historyOfEverything.addRating(5);console.log(historyOfEverything.getAverageRating());const speed = new Movie('Jan de Bont', 'Speed', 116);speed.toggleCheckOutStatus();console.log(speed.isCheckedOut);speed.addRating(1);speed.addRating(1);speed.addRating(5);console.log(speed.getAverageRating());

Answer 1

您可以抛出这样的错误。

throw new Error("messages");

此外，我建议您用 AND 而不是 OR 来描述有效输入的范围 value < 5 && value > 1

function addRating(value) {

  if (value < 5 && value > 1) {

    console.log("Everything is okay");

  } else {

    throw new Error("Invalid Input. Please enter an integer between 1-5.");

  }

}

addRating(12);

Answer 2

您可以抛出如下错误：

function addRating(newRating) {

  if (newRating < 1 || newRating > 5) {

    throw "Invalid Input. Please enter an integer between 1-5.";

  } else {

    this.ratings.push(newRating);

  }

}

addRating(7);

Answer 3

你可以用一个提示去老派，然后把它放在while循环中。在此答案中，如果传递的值正确，则忽略 while 循环。我注释了你对我的测试答案的推动。

function addRating(newRating) {

   while(newRating < 1 || newRating > 5){

     newRating = Number(prompt("Invalid Input. Please enter an integer between 1-5."));

  }

  

  //this.ratings.push(newRating);

}

addRating(41);