如果属性与比较值不匹配，如何更改数组中对象属性的值？

Question

我想返回具有与valuesToCompare数组值不匹配的属性的数组const arr = [{value: "test1", name: "name1"},{value: "test2", name: "name1"},{value: "test3", name: "name1"},{value: "test3", name: "name2"},{value: "test4", name: "name2"},]const valuesToCompare = ["test1", "test2", "test3", "test4"]预期产出[{value: "test4", name: "name1"},{value: "test1", name: "name2"},{value: "test2", name: "name2"},]

Answer 1

我不确定您是否想要根据值数组进行匹配或排除，因此请提供两者：

const arr = [{

    value: "test1",

    name: "name1"

  },

  {

    value: "test2",

    name: "name1"

  },

  {

    value: "test3",

    name: "name1"

  },

  {

    value: "test3",

    name: "name2"

  },

  {

    value: "test4",

    name: "name2"

  },

]

const valuesToCompare = ["test1", "test2"]

const excluding = arr.filter(obj => !valuesToCompare.includes(obj.value))

console.log("Excluding values:")

console.log(excluding)

const matching = arr.filter(obj => valuesToCompare.includes(obj.value))

console.log("Matching values:")

console.log(matching)

Answer 2

你可以像下面这样做：

• 分组arr依据name

• 对于每个分组，过滤值

• 将每个组展平为对象

const arr = [

  { value: "test1", name: "name1" },

  { value: "test2", name: "name1" },

  { value: "test3", name: "name1" },

  { value: "test3", name: "name2" },

  { value: "test4", name: "name2" },

];

const valuesToCompare = ["test1", "test2", "test3", "test4"];

const groupByName = arr.reduce((acc, el) => {

  if (acc[el.name]) {

    acc[el.name].push(el.value);

  } else {

    acc[el.name] = [el.value];

  }

  return acc;

}, {});

const res = Object.entries(groupByName)

  .map(([k, v]) => [k, valuesToCompare.filter((vtc) => !v.includes(vtc))])

  .map(([k, v]) => v.map((v) => ({ name: k, value: v })))

  .flat();

console.log(res);

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