Python 异步响应时间

Question

我正在尝试学习 asyncio 和 aiohttp。我有以下代码来使用 asyncio 查询一堆 URL。import aiohttpimport asynciosync def fetch(session, url):    async with session.get(url) as response:        return await response.text()async def main():    urls = [            'http://yahoo.com',            'https://google.com',            'http://bing.com'        ]    tasks = []    async with aiohttp.ClientSession() as session:        for url in urls:            tasks.append(fetch(session, url))        htmls = await asyncio.gather(*tasks)        for html in htmls:            print(html[:100] + "\n")    if __name__ == '__main__':    loop = asyncio.get_event_loop()    loop.run_until_complete(main())如何获取每个异步查询的响应时间？我的第一个想法是只使用计时器，但我不知道在这种情况下如何使用它。我尝试搜索是否有人做过类似的事情，但找不到任何东西。

Answer 1

async def fetch(session, url):

    """[Coroutine to send HTTP request to URLs provided]

    Args:

        session ([aiohttp Client Session object]): [session object]

        url ([string]): [URL to query]

    Returns:

        [list]: [response url, status and time taken]

    """

    tic = time.perf_counter() # Start timer

    try:

        response = await session.request(method='GET', url=url, timeout=10)

        toc = time.perf_counter() # Stop timer

        time_taken  = toc - tic # Calculate time taken to get response

        response.raise_for_status()

        print("URL : ", url)

        print("HTTP Status : ", response.status)

        print(f"Time taken : {time_taken:4f} seconds")

        print()

        return str(response.url), response.status, time_taken

    

    except HTTPError as http_err:

        logging.error(http_err)

    except Exception as err:

        logging.error(err)