使用我的代码中的 2 个变量创建循环（Android）

Question

道路规则应用程序我有一个活动，其中将根据票号显示问题和答案（20 个问题和 5x20 个答案）。字符串中包含的问题和答案重新排序并排序。我的代码非常糟糕，我想通过循环来简化，就像有问题 [q] 但有 2 个变量的情况一样。请帮帮我。https://play.google.com/store/apps/details?id=ua.in.sil.cryzalit.mybiletsnumber = intent.getStringExtra("number");  for( int i = 1; i < 21; i++)    {        q[i]= this.getResources().getIdentifier("q"+i+"_" + number, "string", this.getPackageName());    }    int a1_1 = this.getResources().getIdentifier("a1_1_" + number, "string", this.getPackageName());    int a2_1 = this.getResources().getIdentifier("a2_1_" + number, "string", this.getPackageName());    int a3_1 = this.getResources().getIdentifier("a3_1_" + number, "string", this.getPackageName());    int a4_1 = this.getResources().getIdentifier("a4_1_" + number, "string", this.getPackageName());    int a5_1 = this.getResources().getIdentifier("a5_1_" + number, "string", this.getPackageName());\\\\    int a1_20 = this.getResources().getIdentifier("a1_20_" + number, "string", this.getPackageName());    int a2_20 = this.getResources().getIdentifier("a2_20_" + number, "string", this.getPackageName());    int a3_20 = this.getResources().getIdentifier("a3_20_" + number, "string", this.getPackageName());    int a4_20 = this.getResources().getIdentifier("a4_20_" + number, "string", this.getPackageName());    int a5_20 = this.getResources().getIdentifier("a5_20_" + number, "string", this.getPackageName());

Answer 1

可以使用二维数组，代码如下：

int answers[][] = new int[20][5];

for( int i = 0; i < 20; i++) {

    for( int j = 0; j < 5; j++){

         answers[i][j] = this.getResources().getIdentifier("a"+(j+1)+"_"+(i+1)_" + number, "string", this.getPackageName());

    }

}

我也不确定q数组，因为它将从 0 开始，只需重新访问它即可。