1 回答
TA贡献1872条经验 获得超3个赞
您看不到StringBuilder
,因为使用 a 的结果StringBuilder
是 a String
。这StringBuilder
是在幕后使用的。
例子
String[] input = { "Hell", "oW", "orld" };
String joined = Stream.of(input).collect(Collectors.joining());
System.out.println(joined); // prints: HelloWorld
如果你在没有流媒体的情况下执行此操作,你会这样做:
StringBuilder buf = new StringBuilder();
for (String s : input)
buf.append(s);
String joined = buf.toString();
这也是流正在做的事情。如果你查看源码joining(),你会发现:
public static Collector<CharSequence, ?, String> joining() {
return new CollectorImpl<CharSequence, StringBuilder, String>(
StringBuilder::new, StringBuilder::append,
(r1, r2) -> { r1.append(r2); return r1; },
StringBuilder::toString, CH_NOID);
}
正如您所看到的,它还使用new StringBuilder()
、append(CharSequence s)
和toString()
。
另外两个重载joining(CharSequence delimiter)
和joining(CharSequence delimiter, CharSequence prefix, CharSequence suffix)
,使用StringJoiner
而不是StringBuilder
。
String[] input = { "Hell", "oW", "orld" };
String joined = Stream.of(input).collect(Collectors.joining());
System.out.println(joined); // prints: HelloWorld
如果你在没有流媒体的情况下执行此操作,你会这样做:
StringBuilder buf = new StringBuilder();
for (String s : input)
buf.append(s);
String joined = buf.toString();
这也是流正在做的事情。如果你查看源码joining(),你会发现:
public static Collector<CharSequence, ?, String> joining() {
return new CollectorImpl<CharSequence, StringBuilder, String>(
StringBuilder::new, StringBuilder::append,
(r1, r2) -> { r1.append(r2); return r1; },
StringBuilder::toString, CH_NOID);
}
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