使用python进行bs4过滤

Question

我正在尝试编写一个检查 Steam 商店的脚本，但在过滤掉代码中没有折扣的所有列表时遇到问题。我只想保留带有 span 标签的列表以及<span>-percentage</span>其中的列表，而不是没有的列表。这是我的代码：from urllib.request import urlopenfrom datetime import dateimport requests as rqinp = str(input('what would you like to search up?'))w = ('https://store.steampowered.com/search/?term=' + inp)page = rq.get(w)soup = bsoup(page.content, 'html.parser')soup.prettify()sales = soup.find_all('div', class_="responsive_search_name_combined")for sale in sales:    p = soup.find('div', class_="col search_price responsive_secondrow")    d = soup.find_all('div', class_="col search_discount responsive_secondrow")    n = soup.find('span', class_="title")    if None in (d, n, p):        continue    print(d)和输出（包含我想要过滤掉的东西/我想要保留的东西）<span>-16%</span></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"><span>-19%</span></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow"></div>, <div class="col search_discount responsive_secondrow">等等，我尝试替换d = soup.find_all('div', class_="col search_discount responsive_secondrow")为，d = soup.find_all('span', string="-16%")看看是否有效，但没有。我想保留 span 标签，但不保留 div 标签，有人可以帮忙吗？

Answer 1

您只需try-except在最后一个for循环中添加一个块即可解决您的问题。这是完整的代码：

from urllib.request import urlopen

from datetime import date

import requests as rq

from bs4 import BeautifulSoup as bsoup

inp = str(input('what would you like to search up?'))

w = ('https://store.steampowered.com/search/?term=' + inp)

page = rq.get(w)

soup = bsoup(page.content, 'html.parser')

soup.prettify()

sales = soup.find_all('div', class_="responsive_search_name_combined")

final = []

for sale in sales:

    p = soup.find('div', class_="col search_price responsive_secondrow")

    d = soup.find_all('div', class_="col search_discount responsive_secondrow")

    n = soup.find('span', class_="title")

    try:

        for element in d:

            span = element.span

            if span:

                final.append(span.text)

    except:

        pass

print(final)

输出：

what would you like to search up?>? among us

['-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%', '-10%', '-25%']