尝试将输入转换为列表

Question

我正在尝试从用户那里获取 2 个点的输入并输出距离。我陷入了将输入转换为输出列表的困境。我可能以错误的方式思考它，任何帮助我走向正确方向的帮助都是值得赞赏的。import mathp1 = input("please enter x1 and y1: ")p2 = input("please enter x2 and y2: ")x1y1 = p1.split(',')x2y2 = p2.split(',')distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )print(distance)

Answer 1

您可以使用列表理解将输入转换为ints，然后进行解构赋值以将它们分配给两个不同的变量：

from math import sqrt

[x1, y1] = [int(n) for n in input("please enter x1 and y1: ").split()]

[x2, y2] = [int(n) for n in input("please enter x2 and y2: ").split()]

print(f"Distance: {sqrt((x1-x2)**2+(y1-y2)**2)}")

Answer 2

首先将每个元素转换为 int：

p1 = input("please enter x1 and y1: ")

p2 = input("please enter x2 and y2: ")

x1y1 = [int(x) for x in p1.split(',')]

x2y2 = [int(y) for y in p2.split(',')]

Answer 3

这可以帮助：

from math import sqrt

xi, yi = [int(i) for i in input().split()]

xf, yf = [int(i) for i in input().split()]

print(math.sqrt((xf-xi)**2 + (yf-yi)**2))

Answer 4

import math

p1 = input("please enter x1 and y1: ")

p2 = input("please enter x2 and y2: ")

x1y1 = [int(num) for num in p1.split(',')]

x2y2 = [int(num) for num in p2.split(',')]

distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )

print(distance)

Str 应转换为 int。

Answer 5

您可以使用map()轻松转换为int

import math

p1 = input("please enter x1 and y1: ")

p2 = input("please enter x2 and y2: ")

x1y1 = list(map(int, p1.split(',')))

x2y2 = list(map(int, p2.split(',')))

distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )

print(distance)