PHP 特定字符之前和之后的子字符串，直到空格、逗号...？

Question

我正在尝试抓取一封电子邮件。假设我有一个很长的字符串：$str = "this is the email [e-mail] which you might want to scrape";$needle_1 = "@";$needle_2 = array("[ ]","[,]","["]");我想提取电子邮件。我认为使用@是解决方案。 所以基本上，我需要获取@之前和之后的所有字符，直到空格、逗号或"。目前最好的试用是：$string = 'this is the email [e-mail] which you might want to scrape';$template = "/[\w]+[@][\w]+[.][\w]+/";preg_match_all($template, $string, $matches);var_dump($matches);我怎样才能做到这一点？

Answer 1

我认为它看起来更好

  $string = 'this is the email [e-mail] which you might want to scrap';

  $template = "/[\w]+[@][\w]+[.][\w]+/";

  preg_match_all($template, $string, $matches);

  var_dump($matches);

Answer 2

您应该为此创建一个正则表达式：

<?php 

    $str = "this is the email [e-mail] which you might want to scrap";

    $pattern = '/[a-z0-9_\-\+\.]+@[a-z0-9\-]+\.([a-z]{2,4})(?:\.[a-z]{2})?/i';

    preg_match_all($pattern, $str, $matches);

    var_dump($matches[0]);

?>