对数组中大于输入值的数字求和

Question

需要将数组中大于输入数字的所有数字相加。种子只是为了可以复制输出。例子：[12,16,45,3,32]输入值：30输出：77import java.util.*;    public class SumAbove {        public static void main(String[] args) {            Scanner scnr = new Scanner(System.in);            int seed = scnr.nextInt();            Random rand = new Random(seed);            System.out.println("Enter a positive integer between 1-100 to search above:");            int minVal = scnr.nextInt();            int[] arr = new int[rand.nextInt(100)+1];            for (int i=0; i<arr.length; i++) {                arr[i] = rand.nextInt(100)+1;            }            System.out.println(Arrays.toString(arr));             int sum = 0;             for (int i=0; i<arr.length; i++) {             if (arr[i]>minVal) {                    sum += i;                }             }            System.out.println(sum);        }    }

Answer 1

sum += i;您sum += arr[i];也只需要一个循环（因为您知道第一个循环之前的最小值），而不是您想要的（如前所述）。喜欢，

int minVal = scnr.nextInt(), sum = 0;

int[] arr = new int[rand.nextInt(100) + 1];

for (int i = 0; i < arr.length; i++) {

    arr[i] = rand.nextInt(100) + 1;

    if (arr[i] > minVal) {

        sum += arr[i];

    }

}

System.out.println(Arrays.toString(arr));

System.out.println(sum);

Answer 2

sum += i用。。。来代替sum += arr[i]。

变量i只是位置。arr[i]是该位置的值。

Answer 3

public static void main(String[] args) {

    int nums[] = { 12, 16, 45, 3, 32 };

    int value;

    int sum = 0;

    System.out.println("Enter a positive integer between 1-100 to search above: ");

    Scanner sc = new Scanner(System.in);

    value = sc.nextInt();

    for (int i = 0; i < nums.length; i++) {

        if (nums[i] > value)

            sum = nums[i] + sum;

    }

    System.out.println(sum);

}

Answer 4

以下是如何在 Java 8+ 中使用流来实现这一点。

      int nValues = 5;

      int minValue = 1;

      int maxValue = 30;

      Random r = new Random();

      for (int i = 0; i < 10; i++) {

         int[] values = r.ints(nValues, minValue, maxValue + 1).toArray();

         // min to sum is the threshold

         int minToSum = r.nextInt(7) + 10; // between 10 an 16 inclusive

         int sum = Arrays.stream(values).filter(m -> m > minToSum).sum();

         System.out.println("sum = " + sum + " for greater than " + minToSum

               + " : " + Arrays.toString(values));

      }

以下输出。

sum = 65 for values greater than 11 : [2, 10, 14, 23, 28]

sum = 92 for values greater than 10 : [13, 18, 15, 19, 27]

sum = 94 for values greater than 12 : [25, 6, 14, 25, 30]

sum = 54 for values greater than 10 : [14, 8, 14, 26, 5]

sum = 22 for values greater than 15 : [15, 8, 13, 22, 14]

sum = 28 for values greater than 13 : [3, 28, 9, 6, 5]

sum = 87 for values greater than 13 : [5, 18, 25, 21, 23]

sum = 31 for values greater than 13 : [16, 7, 12, 2, 15]

sum = 42 for values greater than 15 : [7, 22, 20, 10, 5]

sum = 40 for values greater than 12 : [2, 2, 13, 27, 9]