将 numpy 数组转换为整数数组

Question

我有数组length = 7angle = 30  x = [1.21660254e+02, 1.71660254e+02, 2.38660254e+02, 2.05660254e+02]我试过这个P2x =  int(np.round(x + length * math.cos(math.radians(-angle))))给我错误TypeError: only size-1 arrays can be converted to Python scalars

Answer 1

math如果您已经在使用，则不需要该模块numpy

import numpy as np

length = 7

angle = 30 

x = [1.21660254e+02, 1.71660254e+02, 2.38660254e+02, 2.05660254e+02]

xP2x = np.round(np.array(x) + length * np.cos(np.radians(-angle))).astype(int)

print(xP2x)

出去：

[128 178 245 212]