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TA贡献1793条经验 获得超6个赞
您的代码有几个问题。首先,当您使用该构造时:
with concurrent.futures.ThreadPoolExecutor() as executor:
f1 = executor.submit(self.pop_up1())
f2 = executor.submit(self.test())
有一个隐含的executor.sutdown()调用,等待提交的任务完成。请参阅文档。由于您在主线程上使用此构造,因此所有 GUI 更新都将被阻止,直到所有提交的任务完成。因此,您通常不应在 kivy 应用程序的主线程上使用该构造。
第二个问题是 an 的创建和显示MDDialog应该在主线程上完成,因此提交类似 的方法pop_up1()可能executor会出现问题。
第三个问题是您尝试重用MDDialogwithif not self.dialog:条件。无论如何你都不能重复使用MDDialog。
因此,考虑到所有这些,这里是代码的修改版本,可以实现我认为您想要的功能:
from kivy.clock import Clock, mainthread
from kivy.lang import Builder
from kivy.uix.boxlayout import BoxLayout
from kivymd.app import MDApp
from kivymd.uix.dialog import MDDialog
import concurrent.futures
KV = '''
<Content>
orientation: "vertical"
spacing: -40
MDSpinner:
size_hint: None, None
size: dp(46), dp(46)
pos_hint: {'center_x': 0.1}
active: True
MDLabel:
text: "Processing..."
pos_hint: {'center_x': .7}
FloatLayout:
MDFlatButton:
text: "ALERT DIALOG"
pos_hint: {'center_x': .5, 'center_y': .5}
on_release: app.start()
'''
class Content(BoxLayout):
pass
class Example(MDApp):
dialog = None
def build(self):
return Builder.load_string(KV)
def start(self):
# this must be done on the main thread
self.pop_up1()
executor = concurrent.futures.ThreadPoolExecutor()
# f1 = executor.submit(self.pop_up1) # this must be done on the main thread
f2 = executor.submit(self.test)
def pop_up1(self):
'''Displays a pop_up with a spinning wheel'''
self.dialog = MDDialog(
size_hint=(.45, None),
auto_dismiss=True,
type="custom",
content_cls=Content(),
)
self.dialog.open()
def test(self):
'''Counts to 1000000 and then it closes pop_up1 and opens pop_up2'''
for number in range(100000):
print(number)
self.dismiss()
Clock.schedule_once( self.pop_up2) # pop_up2() must be done on the main thread
def pop_up2(self,*args):
self.dialog = MDDialog(
title="Done",
size_hint=(.6, None),
text="Done",
)
self.dialog.open()
@mainthread
def dismiss(self, *args):
self.dialog.dismiss()
Example().run()
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