AttributeError：“str”对象在 tkinter 标签中没有属性“tk”

Question

我正在制作一个程序来跟踪印度的新冠病例。我的程序的命令行版本也取得了成功。于是，我想到了升级到GUI版本。但我收到一个错误。这是Python代码：-from bs4 import BeautifulSoupimport urllib.requestfrom tkinter import *root = Tk()print("Retrieving Source....")site_data = urllib.request.urlopen("https://covidindia.org")site_html = BeautifulSoup(site_data , 'html.parser')data = site_html.find_all(style = "text-align: center;")data2= site_html.find_all("h1")# GUI Versionupdated_as = Label("Updated As:-", data[0].get_text()[1:-1])Total_Cases = Label(data2[1].get_text())Active_Cases = Label("Active Cases:", data[2].get_text(), "("+data[3].get_text()+")")Recov_Cases = Label("Recovered Cases:", data[5].get_text(), "("+data[6].get_text()+")")Deaths = Label("Deaths:", data[8].get_text(), "("+data[9].get_text()+")")Tests_Done = Label("Tests Done:", data[11].get_text(), "("+data[12].get_text()+")")# Command Line Version# print("Updated As:-", data[0].get_text()[1:-1])# print(".................................................")# print(data2[1].get_text())# print("Active Cases:", data[2].get_text(), "("+data[3].get_text()+")")# print("Recovered Cases:", data[5].get_text(), "("+data[6].get_text()+")")# print("Deaths:", data[8].get_text(), "("+data[9].get_text()+")")# print("Tests Done:", data[11].get_text(), "("+data[12].get_text()+")")# input("Press Enter to Exit!")这是错误堆栈：Traceback (most recent call last):File "E:\Files\python\CovidTracker\main.py", line 15, in <module>  updated_as = Label("Updated As:-", data[0].get_text()[1:-1])File "B:\Users\adity\AppData\Local\Programs\Python\Python38- 32\lib\tkinter\__init__.py", line 3143, in __init__  Widget.__init__(self, master, 'label', cnf, kw)File "B:\Users\adity\AppData\Local\Programs\Python\Python38-3 2\lib\tkinter\__init__.py", line 2561, in __init__  BaseWidget._setup(self, master, cnf)File "B:\Users\adity\AppData\Local\Programs\Python\Python38- 32\lib\tkinter\__init__.py", line 2530, in _setup  self.tk = master.tkAttributeError: 'str' object has no attribute 'tk'

Answer 1

试试这个：

updated_as = Label(root, text=("Updated As:-", data[0].get_text()[1:-1]))

updated_as.pack()

我只是使用关键字参数text或tkinter混淆parent位置参数，因为"Updated As:-", data[0].get_text()[1:-1]它是 a str，因此给出了错误。还要确保使用pack()（或任何其他布局管理器）将小部件放在屏幕上。小部件采用的第一个位置参数是master窗口（root在您的情况下），并且text作为关键字参数出现。您还忘记了，root.mainloop()如果没有它，窗口将不会显示。

确保对所有小部件执行相同的操作。

整个工作代码：

from bs4 import BeautifulSoup

import urllib.request

from tkinter import *

root = Tk()

print("Retrieving Source....")

site_data = urllib.request.urlopen("https://covidindia.org")

site_html = BeautifulSoup(site_data , 'html.parser')

data = site_html.find_all(style = "text-align: center;")

data2= site_html.find_all("h1")

# GUI Version

updated_as = Label(root,text=("Updated As:-", data[0].get_text()[1:-1]))

updated_as.pack()

Total_Cases = Label(root,text=(data2[1].get_text()))

Total_Cases.pack()

Active_Cases = Label(root,text=("Active Cases:", data[2].get_text(), "("+data[3].get_text()+")"))

Active_Cases.pack()

Recov_Cases = Label(root,text=("Recovered Cases:", data[5].get_text(), "("+data[6].get_text()+")"))

Recov_Cases.pack()

Deaths = Label(root,text=("Deaths:", data[8].get_text(), "("+data[9].get_text()+")"))

Deaths.pack()

Tests_Done = Label(root,text=("Tests Done:", data[11].get_text(), "("+data[12].get_text()+")"))

Tests_Done.pack()

root.mainloop()

我也认为摆脱它是可以的，root因为你只有一扇窗户，这很好。但关键字参数text很重要。

Answer 2

您是否尝试在将其分配给变量的同一指令中打包（）updated_as？调用 pack() 方法意味着它将返回 None。也许尝试一下

updated_as = Label(args)
updated_as.pack()