PHP 中的多维数组推送

Question

  <?php$userData = [    [        "UID" => "5f10482574d83d4b726fe5",        "name" => "Yug Gill",        "orgID" => "5f10481d74d83d4b726",        "imageURL" => "female.png"    ]];$userProductsData = [    [    "UPID" => "5f10482574d83d4b6fe007",    "UID" => "5f10482574d83d4b726fe5",    ]];$userDetailsResult = [];foreach ($userData as $key => $value) {    $userData[$key]["UPID"] = $userProductsData[$value["UID"]] ?? [];}预期输出$userData = [    [        "UID" => "5f10482574d83d4b726fe5",        "name" => "Yug Gill",        "orgID" => "5f10481d74d83d4b726",        "imageURL" => "female.png",        "UPID" => "5f10482574d83d4b6fe007"    ]];我有两个UID数组通用的数组，现在我想从中获取 UPID$userProductsData并推入$userData，我尝试过无法正常工作，请有人更新我的代码吗？>

Answer 1

试试这个。

$userData = [

    [

        "UID" => "5f10482574d83d4b726fe5",

        "name" => "Yug Gill",

        "orgID" => "5f10481d74d83d4b726",

        "imageURL" => "female.png"

    ]

];

$userProductsData = [

    [

    "UPID" => "5f10482574d83d4b6fe007",

    "UID" => "5f10482574d83d4b726fe5",

    ]

];

$userDetailsResult = [];

foreach ($userProductsData as $key => $value) {

    $userData[$key]["UPID"] = $value['UPID'];

   

}

print_r($userData);

Answer 2

您$userProductsData是一个常规数组，它有索引 0、1、2 等...然后您尝试通过字符串 key 从此数组中获取项目"5f10482574d83d4b726fe5"。

$userProductsData应该是这样的键数组：

$userProductsData = [

    "5f10482574d83d4b726fe5" => [

        "UPID" => "5f10482574d83d4b6fe007",

        "UID" => "5f10482574d83d4b726fe5",

    ],

];

然后你可以通过 key 从这个数组中获取一个项目"5f10482574d83d4b726fe5"。