如何在 JavaScript 中删除空白数组

Question

我是 JavaScript 新手。初始数据：["Argentina", "Maroon 5:50<br>"]["Australia", "Maroon 5:224<br>"]["Austria", "Maroon 5:42<br>"]["Belgium", "Maroon 5:10<br>"][""]["Brazil", "Maroon 5:187<br>"][""]["Canada", "Maroon 5:160<br>"][""]["China", "Maroon 5:10<br>"][""][""][""][""][""][""][""][""]["France", "Maroon 5:1533<br>"]我的代码：     $.each(resp.result.artists_detail, function(index, item) {  var arr = [];  var pop_val = [];                         var artistdetails="";  for (var i = 0; i < resp.result.artists.length; i++) {    arr.push(item[0].country_name);    if(item[i].play_count != 0){      artistdetails +=item[i].artist_name +':'+ item[i].play_count+'<br>';    }else{      arr.pop(artistdetails);    }    }  arr.push(artistdetails);  arrOfChart.push(arr);});我需要这个结果：["Argentina", "Maroon 5:50<br>"]["Australia", "Maroon 5:224<br>"]["Austria", "Maroon 5:42<br>"]["Belgium", "Maroon 5:10<br>"]["Brazil", "Maroon 5:187<br>"]["Canada", "Maroon 5:160<br>"]["China", "Maroon 5:10<br>"]["France", "Maroon 5:1533<br>"]如何删除空白数组？我正在尝试为数组推送添加数组并为数组弹出删除数组，但我需要一个没有空白数组的数组。

Answer 1

最后做：

arrOfChart = arrOfChart.filter(arr=>!(arr.length == 1 && arr[0] == ""))

console.log(arrOfChart)

>>>[

["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

["Brazil", "Maroon 5:187<br>"],

["Canada", "Maroon 5:160<br>"],

["China", "Maroon 5:10<br>"],

["France", "Maroon 5:1533<br>"]

]

Answer 2

要从数组中删除空值，您需要使用filter函数：

var array = [0, 1, null, 2, "", 3, undefined, 3,,,,,, 4,, 4,, 5,, 6,,,,];

var filtered = array.filter(function (el) {

  return el != "";

});

console.log(filtered);

Answer 3

你只需使用filter

let data = [["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

[""],

["Brazil", "Maroon 5:187<br>"],

[""],

["Canada", "Maroon 5:160<br>"],

[""],

["China", "Maroon 5:10<br>"],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

["France", "Maroon 5:1533<br>"]]

let result = data.filter(([el]) => el);

console.log(result);

Answer 4

通过使用( to ).filter的隐式强制，您可以实现这一点""false

baseArray.filter( subArray => subArray[0]);

const baseArray = [["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

[""],

["Brazil", "Maroon 5:187<br>"],

[""],

["Canada", "Maroon 5:160<br>"],

[""],

["China", "Maroon 5:10<br>"],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

["France", "Maroon 5:1533<br>"]

];

const result = baseArray.filter( subArray => subArray[0]);

console.log(result);