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在多个轴上对二维数组进行排序

在多个轴上对二维数组进行排序

慕莱坞森 2023-10-18 21:09:08
我有以下数组:tasks = [["LNWBN","2017-08-13","2017-12-24","Corey","Kyle","Kaleb","Reuben"], ["NSXEN","2017-08-20","2017-09-18","Kai"], ["DNMDC","2017-06-19","2017-08-07","Kaleb","Kai","Kyle","Reuben"], ["UYWEQ","2017-04-23","2017-07-18","Corey","Kyle","Reuben","Kai"], ["LIVNH","2017-11-01","2017-12-24","Kaleb","Kai"]]我想按第三列排序,然后按第一列排序,结果是:tasks = [["UYWEQ","2017-04-23","2017-07-18","Corey","Kyle","Reuben","Kai"], ["DNMDC","2017-06-19","2017-08-07","Kaleb","Kai","Kyle","Reuben"], ["NSXEN","2017-08-20","2017-09-18","Kai"], ["LIVNH","2017-11-01","2017-12-24","Kaleb","Kai"],["LNWBN","2017-08-13","2017-12-24","Corey","Kyle","Kaleb","Reuben"]]  我尝试使用 lexsort:a = np.array(tasks)ind = np.lexsort((a[:,2],a[:,0]))    sorted_tasks = a[ind]这是这里的最佳解决方案Sorting a 2D numpy array by multiple axis 但出现以下错误:  ind = np.lexsort((a[:,2],a[:,0]))IndexError: too many indices for array: array is 1-dimensional, but 2 were indexed我不必使用 numpy,但这是我发现按多个轴对 2D 数组进行排序的唯一方法
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MYYA

TA贡献1868条经验 获得超4个赞

你为什么不试试 python 的sorted:


sorted(tasks, key=lambda x: (x[2],x[0]))

输出:


[['UYWEQ', '2017-04-23', '2017-07-18', 'Corey', 'Kyle', 'Reuben', 'Kai'],

 ['DNMDC', '2017-06-19', '2017-08-07', 'Kaleb', 'Kai', 'Kyle', 'Reuben'],

 ['NSXEN', '2017-08-20', '2017-09-18', 'Kai'],

 ['LIVNH', '2017-11-01', '2017-12-24', 'Kaleb', 'Kai'],

 ['LNWBN', '2017-08-13', '2017-12-24', 'Corey', 'Kyle', 'Kaleb', 'Reuben']]


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反对 回复 2023-10-18
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