如何获取两个月/年点之间的每个月数和年份

Question

我正在创建一个函数，您可以在其中给出起始年、月和结束年、月，并且该函数将在两个给定点之间的每个月和年打印。我已经创建了一个可以完美运行的函数，但我相信这不是一个好的做法，可能有更好的方法来做到这一点。现在我正在寻求您的帮助以找到更好的方法。PS 我无法获取完整日期作为输入。只能获取月份和年份。这是我的代码 -function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {if (($monthstart === null) || ($yearstart === null) || ($monthend === null) || ($yearend === null)) {    $monthend = date('m');    $yearend = date('Y');    if($monthend < 6) {        $yearstart = $yearend - 1;        $monthstart = (($monthend - 5) + 12);    } else {        $yearstart = $yearend;        $monthstart = $monthend - 5;    }}$month_array = array();if ($yearstart > $yearend) {    for ($m=$monthend; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);    for ($y=$yearend+1; $y<$yearstart; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);    for ($m=1; $m<=$monthstart; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);} elseif ($yearend > $yearstart) {    for ($m=$monthstart; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);    for ($y=$yearstart+1; $y<$yearend; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);    for ($m=1; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);} else {    for ($m=$monthstart; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);}return $month_array;}编辑：根据 Nigel Ren 的回答，这是我能想到的最好的方法 - function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {if (($monthstart === null) || ($yearstart === null) || ($monthend === null) || ($yearend === null)) {    $monthend = date('m');    $yearend = date('Y');    if($monthend < 6) {        $yearstart = $yearend - 1;        $monthstart = (($monthend - 5) + 12);    } else {        $yearstart = $yearend;        $monthstart = $monthend - 5;    }}

Answer 1

您可以使用 PHP 的DateInterval类来实现这些目的。试试这个代码

<?php

function getMonthsFromRange($start, $end, $format = 'M Y')

{

    $array = array();

    // Since you wanted 1 month it is Period = 1 Month

    $interval = new DateInterval('P1M');

    $realEnd = new DateTime($end);

    $realEnd->add($interval);

    $period = new DatePeriod(new DateTime($start), $interval, $realEnd);

    // Use loop to store date into array 

    foreach ($period as $date)

        $array[] = $date->format($format);

    // Return the array elements 

    return $array;

}

// Function call with passing the start date and end date 

$months = getMonthsFromRange('2010-10', '2011-11');

print_r($months);

它的输出是：

Array ( [0] => Oct 2010 [1] => Nov 2010 [2] => Dec 2010 [3] => Jan 2011 [4] => Feb 2011 [5] => Mar 2011 [6] => Apr 2011 [7] => May 2011 [8] => Jun 2011 [9] => Jul 2011 [10] => Aug 2011 [11] => Sep 2011 [12] => Oct 2011 [13] => Nov 2011 )

Answer 2

只需在开始日期上添加 1 个月直到结束日期即可完成...

function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {

    $output = [];

    $time   = strtotime($yearstart."-".$monthstart);

    $last   = date('m-Y', strtotime($yearend."-".$monthend));

    do {

        $month = date('m-Y', $time);

        $output[] =  $month;

        $time = strtotime('+1 month', $time);

    }

    while ($month != $last);

    return $output;

}

所以

print_r(get_all_months(4,2008,2,2010));

给...

Array

(

    [0] => 04-2008

    [1] => 05-2008

    [2] => 06-2008

    [3] => 07-2008

    [4] => 08-2008

    [5] => 09-2008

    [6] => 10-2008

    [7] => 11-2008

    [8] => 12-2008

    [9] => 01-2009

    [10] => 02-2009

    [11] => 03-2009

    [12] => 04-2009

    [13] => 05-2009

    [14] => 06-2009

    [15] => 07-2009

    [16] => 08-2009

    [17] => 09-2009

    [18] => 10-2009

    [19] => 11-2009

    [20] => 12-2009

    [21] => 01-2010

    [22] => 02-2010

)

Answer 3

也许你正在寻找这样的东西：

function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {

    $month_array = [];

    if ($yearstart == $yearend)

        for ($m=$monthstart; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);

    else {

        for ($m=$monthstart; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);

        for ($y=$yearstart+1; $y<$yearend; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);

        for ($m=1; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);

    }

    return $month_array;

}

Answer 4

使用DateTime类和DateInterval，您可以创建指定范围的 DateTime 对象的生成器：

<?php

function get_all_months(int $monthstart, int $yearstart, int $monthend, int $yearend) {

        $onemonth = new DateInterval('P1M'); // one month interval

        $timeperiod = new DatePeriod(

                DateTime::createFromFormat('Y-m', "{$yearstart}-{$monthstart}"),

                $onemonth,

                DateTime::createFromFormat('Y-m', "{$yearend}-{$monthend}")->add($onemonth)

        );

        foreach ($timeperiod as $pos) {

                yield clone $pos;

        }

}

foreach (get_all_months(12, 2009, 1, 2020) as $month) {

        echo "{$month->format('Y-m')}\n";

}

DateTime 应该比普通字符串或数字数组更灵活地使用

Answer 5

如果我理解正确的话 - 你会得到数字形式的月份和数字形式的年份，例如 6 和 1997。如果我们假设开始年份总是小于结束年份，我建议这样做。

function distanceBetweenDates(int $sm, int $sy, int $em, int $ey) {

    $monthsBetweenYears = ($ey - $sy + 1) * 12;

    $distanceBetweenMonths = $monthsBetweenYears - $sm - (12 - $em);

    

    $startMonth = $sm + 1;

    $startYear = $sy;

    

    while ($distanceBetweenMonths > 0) {

        if ($startMonth <= 12) {

            echo $startMonth . ' - ' . $startYear;

        } else {

            $startMonth = 1;

            $startYear++;

            echo $startMonth . ' - ' . $startYear;

        }

        echo "\n";

        $startMonth++;

        $distanceBetweenMonths--;

    }

}

您可能需要查看的唯一事情是计算中是否包含或排除给定的月份。

这里唯一缺少的是验证，因为如果您在方法内使用类型，则可以“跳过”某种验证。