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TA贡献1770条经验 获得超3个赞
我如何在 switch 中使用成员的用户名来调用成员的个人资料,因为 $thePage 数组中没有每个用户名。
只需将所有内容传递给index.php
.htaccess:
# Activate rewrite engine
RewriteEngine on
RewriteBase /root/
# If the request is not for a valid directory, file or symlink
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-l
# Redirect all requests to index.php
RewriteRule ^(.*)$ index\.php?/$1 [QSA]
您只需将其传递$_REQUEST['username']给 profile.php,然后渲染您的页面。
就像是:
索引.php
// you can do this better, this is just an example:
$request_uri = $_SERVER['REQUEST_URI'];
$params_offset = strpos($request_uri, '?');
$request_path = '';
$request_params = [];
echo 'request_uri = ', $request_uri, '<br>', PHP_EOL;
if ($params_offset > -1) {
$request_path = substr($request_uri, 0, $params_offset);
$params = explode('&', substr($request_uri, $params_offset + 1));
foreach ($params as $value) {
$key_value = explode('=', $value);
$request_params[$key_value[0]] = $key_value[1];
}
} else {
$request_path = $request_uri;
}
echo 'request_path = ', $request_path, '<br>', PHP_EOL;
echo 'request_params = ', PHP_EOL; print_r($request_params);
if (preg_match('~/root/(photos|videos|albums)/([\w-]+)~', $request_uri, $match)) {
print_r($match);
unset($match);
require_once('photos_videos_albums.php');
} else if (preg_match('~/root/([\w-]+)~', $request_uri, $match)) {
$username = $match[1];
unset($match);
require_once('profile.php');
} else if ($request_path == '/root/') {
echo 'HOME';
exit();
} else {
header('HTTP/1.0 404 Not Found');
echo "<h1>404 Not Found</h1>";
echo "The page that you have requested could not be found.";
}
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