如何更改此代码以不打印未使用的硬币=0？

Question

我正在尝试构建一个功能，当人们输入金额后，它会显示他们需要的最小硬币或纸币数量。但这有什么方法可以让我改变它，这样它就不会打印未使用的硬币的名称和数量吗？（作为初学者）感谢您的帮助！（可以用for循环来处理吗？）

Answer 1

循环可用于遍历笔记列表，并且在循环内，如果发现有任何笔记被计数，则可以打印该笔记。

notes=[1000,500,100,50,20,10,5,2,1]

amount=int(input('Enter an amount: '))

print('Total number of notes/coins=')

for notesAmount in notes:

    if amount>=notesAmount:

       notesCount=amount//notesAmount

       amount%=notesAmount

       if notesCount>0:

          print(notesAmount, ":", notesCount)

Answer 2

不要为每个面额保留一个变量，而是保留一个字典并根据所使用的面额更新 key: val 。查看代码

amount=int(input('Enter an amount: '))

denominations = dict()

print('Total number of notes/coins=')

if amount>=1000:

    denominations['1000'] = amount//1000

    amount%=1000    

if amount>=500:

    denominations['500'] = amount//500

    amount= amount%500

if amount>=100:

    denominations['100'] = amount//100

    amount= amount%100

if amount>=50:

    denominations['50'] = amount//50

    amount= amount%50    

if amount>=20:

    denominations['20'] = amount//20

    amount= amount%20    

if amount>=10:

    denominations['10'] = amount//10

    amount= amount%10

if amount>=5:

    denominations['5'] = amount//5

    amount= amount%5   

if amount>=2:

    denominations['2'] = amount//2

    amount= amount%2    

if amount>=1:

    denominations['1'] = amount//1

for key, val in denominations.items():

    print(f"{key}: {val}")

Enter an amount: 523

Total number of notes/coins=

500: 1

20: 1

2: 1

1: 1

如果使用如下所示的简单逻辑，则可以减少代码行数，

def find_denominations():

    

    amount=int(input('Enter an amount: '))

    

    denominations = dict()

    

    DENOMINATIONS = [1000, 500, 100, 50, 20, 10, 5, 2, 1]

       

    print('Total number of notes/coins=')

    

    for d in DENOMINATIONS:

        if amount >= d:

            denominations[d] = amount // d

            amount %= d

    for key, val in denominations.items():

        print(f"{key}: {val}") 

Answer 3

Sreerams 的类似实现使用 while 循环而不是 for 循环：

amount = int(input("Enter an amount: "))

counter = amount

pos = 0

notes = [1000, 500, 100, 50, 20, 10, 5, 2, 1]

output = []

while counter > 0:

    remainder = counter % notes[pos]

    sub = counter - remainder

    num = int(sub / notes[pos])

    counter -= sub

    output.append({notes[pos]: num})

    pos += 1

print("Total number of notes/coins=")

for r in output:

    for k,v in r.items():

        if v > 0:

            print("{}: {}".format(k, v))

请注意，Sreerams 代码优于我的代码，它更易于阅读，并且在规模上性能更高。