1 回答
TA贡献1909条经验 获得超7个赞
请参阅下面的代码,只是一些三角学知识。
canvas = document.getElementById("canvas");
ctx = canvas.getContext("2d");
ctx.lineCap = "round";
ctx.lineWidth = 5;
function drawLineArrowhead(p1, p2, startSize, endSize) {
ctx.beginPath()
ctx.moveTo(p1.x, p1.y);
ctx.lineTo(p2.x, p2.y);
if (startSize > 0) {
lineAngle = Math.atan2(p2.y - p1.y, p2.x - p1.x);
delta = Math.PI/6
for (i=0; i<2; i++) {
ctx.moveTo(p1.x, p1.y);
x = p1.x + startSize * Math.cos(lineAngle + delta)
y = p1.y + startSize * Math.sin(lineAngle + delta)
ctx.lineTo(x, y);
delta *= -1
}
}
if (endSize > 0) {
lineAngle = Math.atan2(p1.y - p2.y, p1.x - p2.x);
delta = Math.PI/6
for (i=0; i<2; i++) {
ctx.moveTo(p2.x, p2.y);
x = p2.x + endSize * Math.cos(lineAngle + delta)
y = p2.y + endSize * Math.sin(lineAngle + delta)
ctx.lineTo(x, y);
delta *= -1
}
}
ctx.stroke();
}
drawLineArrowhead({x:10, y:10}, {x:100, y:20}, 0, 30)
drawLineArrowhead({x:20, y:25}, {x:140, y:120}, 20, 20)
drawLineArrowhead({x:140, y:20}, {x:80, y:50} , 20, 0)
drawLineArrowhead({x:150, y:20}, {x:150, y:90}, 20, 5)
drawLineArrowhead({x:180, y:90}, {x:180, y:20}, 20, 5)
drawLineArrowhead({x:200, y:10}, {x:200, y:140}, 10, 10)
drawLineArrowhead({x:220, y:140}, {x:220, y:10}, 10, 20)
<canvas id="canvas">
如果运行它,您应该会看到一些示例。
有drawLineArrowhead
4 个参数,(p1, p2, startSize, endSize)
前两个是线条的起点和终点,最后两个是箭头大小,只是为了让最终用户控制末端的箭头有多大,如果我们想要的话删除它们我们设置为0。
- 1 回答
- 0 关注
- 72 浏览
添加回答
举报