比较列表并获取每个元素的匹配百分比

Question

我有两个 python 列表。A= ['today is sunday', 'today is wednesday']B= ['today is sunday', 'today is      Monday'....'today is Saturday'] For elm in A:     If elm in B:        print ("not ok")      else:        print ("ok")我想计算两个 python 列表之间元素匹配的百分比。所需的匹配百分比计算如图所示：

Answer 1

有可能 ：

A= ['today is sunday', 'today is wednesday']

B= ['today is sunday', 'today is monday', 'today is Saturday']

match_percent = (len(set(B).intersection(set(A))))/len(B)*100

print(match_percent)

Answer 2

我不确定您想要计算的确切匹配百分比，因此我冒昧地计算为match_count / max(list_a_size, list_b_size)。

def intersection(lst1, lst2): 

    lst3 = [value for value in lst1 if value in lst2] 

    return len(lst3)

def maximum(a, b): 

    if a >= b: 

        return a 

    else: 

        return b 

A= ['today is sunday', 'today is wednesday']

B= ['today is sunday', 'today is Monday', 'today is Saturday']

match_percent = intersection(A, B) / maximum(len(A),len(B))

print(match_percent)

输出：

0.3333333333333333