JsonConvert 将十进制反序列化为 jtoken 将其转换为科学数字

Question

我有一个带有对象属性的类，如果我使用该属性的十进制值创建该类并序列化它，该值看起来很好：var testObject = new TestObject{    TestDecimal = 8801203167395152041.7m};var serialized = Newtonsoft.Json.JsonConvert.SerializeObject(testObject);serialized.Dump(); // returns {"TestDecimal":8801203167395152041.7}但是，如果我尝试使用 jtoken 反序列化该值，该值将变为科学值并保存为双精度值，以下是整个代码：void Main(){    var testObject = new TestObject{        TestDecimal = 8801203167395152041.7m    };    var serialized = Newtonsoft.Json.JsonConvert.SerializeObject(testObject);    serialized.Dump();    TestObject result = JsonConvert.DeserializeObject<TestObject>(serialized, new JsonSerializerSettings    {        Converters = new List<JsonConverter> { new TestDesiralizer() }    });    testObject.TestDecimal.Dump();    result.TestDecimal.Dump();}public class TestObject{    public object TestDecimal { get; set; }}public class TestDesiralizer : JsonConverter{    public override bool CanConvert(Type objectType)    {        return objectType == typeof(TestObject);    }    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)    {        serializer.Culture = CultureInfo.InvariantCulture;        reader.Culture = CultureInfo.InvariantCulture;        JToken token = serializer.Deserialize<JToken>(reader);        TestObject obj = token.ToObject<TestObject>();        obj.TestDecimal =  decimal.Parse(Convert.ToString(obj.TestDecimal,CultureInfo.InvariantCulture) ?? "",NumberStyles.Any, CultureInfo.InvariantCulture);        return obj;    }    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)    {        throw new NotImplementedException();    }}这导致：1) 8801203167395152041,72) 8801203167395150000反序列化json时如何保留十进制值？

Answer 1

在反序列化期间设置以下内容似乎可以解决该问题：

reader.FloatParseHandling = FloatParseHandling.Decimal