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通过 php 邮件发送时无法为 ics 文件设置名称

通过 php 邮件发送时无法为 ics 文件设置名称

PHP
千万里不及你 2023-09-22 14:43:30
当我使用 mail() 函数发送文件时,我试图设置文件的名称,我发送了它,但在 gmail 中我收到的是没有扩展名的无名文件。有人可以帮我吗?<?php$temp = tmpfile();fwrite($temp, $ical);rewind($temp);$to_email = 'test@gmail.com';$subject = 'Testing PHP Mail';$message = 'Hola caracola';$from_email = 'test@test.com';$path = stream_get_meta_data($temp)['uri'];$num = md5(time());$headers = "MIME-Version: 1.0\r\n"; // Defining the MIME version $headers .= "From:".$from_email."\r\n"; // Sender Email $headers .= "Reply-To: ".$from_email."\r\n"; // Email addrress to reach back $headers .= "Content-Type: multipart/mixed;\r\n"; // Defining Content-Type $body ="Content-Type: text/calendar; name=invite.ics\r\n"; $body .="Content-Disposition: attachment; filename=\"invite.ics\"\r\n";  $body .= $content; // Attaching the encoded file with email     mail($to_email,$subject,$body,$headers);    fclose($temp);} ?>谢谢
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牛魔王的故事

TA贡献1830条经验 获得超3个赞

我刚刚做到了,我粘贴了下面的代码,问题是 php 将新策略应用于新行标题,所以我只需更改一些代码即可避免此限制并解决问题:


<?php

$temp = tmpfile();


fwrite($temp, $ical);

rewind($temp);

$to_email = 'test@gmail.com';

$subject = 'Testing PHP Mail';

$message = 'Hello';

$from_email = 'test@test.com';

$path = stream_get_meta_data($temp)['uri'];


$eol = PHP_EOL;


$filename = "invite.ics";

$mailto = $to_email;

$from_mail = $from_email;

$from_name = "Events";

$replyto = $from_email;


$file = $path;

$file_size = filesize($path);

$handle = fopen($file, "r");

$content = fread($handle, $file_size);

fclose($handle);

$content = chunk_split(base64_encode($content));

$uid = md5(uniqid(time()));

$header = "From: ".$from_name." <".$from_mail.">".$eol;

$header .= "Reply-To: ".$replyto.$eol;

$header .= "MIME-Version: 1.0\r\n";

$header .= "Content-Type: multipart/mixed; boundary=\"".$uid."\"";


$message = "--".$uid.$eol;

$message .= "Content-Type: application/pdf; name=\"".$filename."\"".$eol; // use different content types here

$message .= "Content-Transfer-Encoding: base64".$eol;

$message .= "Content-Disposition: attachment; filename=\"".$filename."\"".$eol;

$message .= $content.$eol;

$message .= "--".$uid."--";


mail($mailto, $subject, $message, $header);

    

fclose($temp);

?>


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反对 回复 2023-09-22
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