不确定如何推断函数参数类型

Question

使用以下代码，any如果可能的话，我将如何替换 s 。我想删除 TS 中的警告“任何意外。指定不同的类型”interface Props {    isPrime: boolean;}interface Other {    isEdit: boolean;}type TFunc = (a: any, b: any) => any;const myFunc = (c: TFunc) => (a: any) => (b: any) => c(a, b);const funcA = myFunc((props: Props, other: Other) => {    // ..somecode}// Code to call the func A result ect.

Answer 1

使用泛型类型

interface Props {

  isPrime: boolean;

}

interface Other {

  isEdit: boolean;

}

type TFunc<T, U> = (a: T, b: U) => any;

const myFunc = <T, U>(c: TFunc<T, U>) => (a: T) => (b: U) => c(a, b);

const funcA = myFunc<Props, Other>((props: Props, other: Other) => {

  // ..somecode

});