java中排序更改为小数的问题

Question

您好，我需要帮助将零钱排序为小数，如 25 美分、便士、镍币等。它说可能有损转换。这是我的代码：public class Assignment04 {    public static void main(String[] args) {        Scanner stdin = new Scanner(System.in);        System.out.println("Enter your amount");        long amount = stdin.nextLong();        long remainder = Math.round(amount * 100 );        long hundreds = (int) remainder / 10000;        remainder = remainder % 10000;        long fifties = (int) remainder / 5000;        remainder = remainder % 5000;        long twenties = (int)remainder / 2000;        remainder = remainder % 2000;        long tens = (int)remainder / 1000;        remainder = remainder % 1000;        long fives = (int)remainder / 500;        remainder = remainder % 500;        long ones = (int)remainder / 100;        remainder = remainder % 100;        long quarters = remainder / .25;        remainder = remainder % .25;        long dimes =  (int)remainder / .10;        remainder = remainder % .10;        long nickels =  (int)remainder / .5;        remainder = remainder % .5;        double pennies = (int) remainder;        System.out.println(hundreds + "hundred/s");        System.out.println(fifties + "fiftie/s");        System.out.println(twenties + "twentie/s");        System.out.println(tens + "ten/s");        System.out.println(fives + "five/s");        System.out.println(ones + "one/s");        System.out.println(quarters + "quarter/s");        System.out.println(dimes + "dime/s");        System.out.println(nickels + "nickel/s");        System.out.println(pennies + "cent/s");    }}我试图弄清楚如何删除红色下划线，以便它可以正确运行。我已经完成了大部分工作，只是当涉及到小数时我感到困惑。

Answer 1

您的余数字段似乎以美分表示。

• $100 = 10000

• $20 = 2000

• $1 = 100

因此，四分之一应为 25，一角应为 10，五分镍应为 5。

还要更改此：

double pennies = (int) remainder;

对此：

long pennies = remainder;

修复扫描仪输入的 amount 并删除所有最终存储在 long 中的行的 (int) 转换：

public class Assignment04 {

    public static void main(String[] args) {

        Scanner stdin = new Scanner(System.in);

        System.out.println("Enter your amount");

        long remainder = Math.round(stdin.nextDouble() * 100 );

        long hundreds = remainder / 10000;

        remainder = remainder % 10000;

        long fifties = remainder / 5000;

        remainder = remainder % 5000;

        long twenties = remainder / 2000;

        remainder = remainder % 2000;

        long tens = remainder / 1000;

        remainder = remainder % 1000;

        long fives = remainder / 500;

        remainder = remainder % 500;

        long ones = remainder / 100;

        remainder = remainder % 100;

        long quarters = remainder / 25;

        remainder = remainder % 25;

        long dimes = remainder / 10;

        remainder = remainder % 10;

        long nickels = remainder / 5;

        remainder = remainder % 5;

        long pennies = remainder;

        System.out.println(hundreds + "hundred/s");

        System.out.println(fifties + "fiftie/s");

        System.out.println(twenties + "twentie/s");

        System.out.println(tens + "ten/s");

        System.out.println(fives + "five/s");

        System.out.println(ones + "one/s");

        System.out.println(quarters + "quarter/s");

        System.out.println(dimes + "dime/s");

        System.out.println(nickels + "nickel/s");

        System.out.println(pennies + "cent/s");

    }

}

Answer 2

你可以使用 int 。而不是长。我希望这有帮助。谢谢

Scanner stdin = new Scanner(System.in);

            int amount;

            int remainder;

            System.out.print("Enter amount:");

            amount= (int) Math.round(stdin.nextDouble() * 100);

            int hundreds= remainder / 1000;

                if (hundreds > 0) {

                    remainder = remainder% 1000;

                    System.out.println(hundreds + "hundred/s");

                }

     int fifties = remainder / 1000;

                        if (fifties > 0) {

                            remainder = remainder% 1000;

                            System.out.println(fifties + "fiftie/s");

                    }

                // number of twenties for remainder.

                int twenties = change / 2000

                if (twenties > 0) { 

                    remainder= remainder % 2000; // this resets the value of remainder to

                    // the remainder after the twenties are

                    // calculated but only if there was at

                    // least enough to make one twenty

                    System.out.println(twenties + "twentie/s");

                }

                int tens = remainder / 1000;

                if (tens > 0) {

                    remainder = remainder% 1000;

                    System.out.println(tens + " ten/s");

                }

                int fives = remainder/ 500;

                if (fives > 0) {

                    remainder= remainder% 500;

                    System.out.println(fives + " five/s");

                }

                int ones = remainder/ 100;

                if (ones > 0) {

                    remainder = remainder % 100;

                    System.out.println(ones + " one/s");

                }

                int quarters = remainder/ 25;

                if (quarters > 0) {

                    remainder= remainder% 25;

                    System.out.println(quarters + " quarter/s");

                }

                int dimes = remainder/ 10;

                if (dimes > 0) {

                    remainder = remainder % 10;

                    System.out.println(dimes + " dime/s");

                }

                int nickels = remainder/ 5;

                if (nickels > 0) {

                    remainder= change % 5;

                    System.out.println(nickels + " nickel/s");

                }

                int pennies = remainder;

                System.out.println(pennies + " cent/s");

            }

        }

Answer 3

我通过将金额和余数转换为双倍来修复它。