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如果用户单击屏幕上的任意位置如何关闭菜单?

如果用户单击屏幕上的任意位置如何关闭菜单?

慕无忌1623718 2023-09-18 17:25:05
我有下面的代码,它执行以下操作: 1:用户单击按钮,它会打开或关闭下拉菜单 2:用户单击 webslides 元素内的任何位置,如果显示,它将关闭菜单问题是网页幻灯片位于按钮下方,我希望用户也单击标题以便在显示菜单时能够不显示菜单,但这不起作用。相反,无论我尝试单击按钮打开菜单多少次,该按钮都不会显示菜单,var menu = document.getElementsByClassName("dropdown-content")[0];var header = document.getElementById('header');var webslidesBody = document.getElementById('webslides');function lessonSelectionFunction() {  if (menu.style.display === "none") {    menu.style.display = "block";  } else {    menu.style.display = "none";  }}webslidesBody.onclick = function() {  menu.style.display = "none";}header.onclick = function() {  menu.style.display = "none";}<html><head>  <!-- Google Fonts -->  <link href="https://fonts.googleapis.com/css?family=Roboto:100,100i,300,300i,400,400i,700,700i%7CMaitree:200,300,400,600,700&subset=latin-ext" rel="stylesheet" />  <!-- Optional - CSS SVG Icons (Font Awesome) -->  <link rel="stylesheet" type='text/css' media='all' href="static/css/svg-icons.css" />  <!-- CSS Webslides -->  <link rel="stylesheet" type='text/css' media='all' href="static/css/webslides.css" />  <meta name="viewport" content="width=device-width, initial-scale=1.0">  <meta charset="UTF-8"></head><body>  <header id="header">    <nav role="navigation" class="nav">      <div class="dropdown">        <button class="dropbtn" style="text-transform: none;" onclick="lessonSelectionFunction()">Lesson Selection</button>        <div class="dropdown-content" style="display:none;">          <a href="#slide=1">Introduction</a>          <a href="#slide=4">Lesson 1: Methodologies and Development Lifecycle</a>          <a href="#slide=18">Lesson 2: IT Support</a>          <a href="#slide=29">Lesson 3: Testing Foundations</a>          <a href="#slide=42">Lesson 4: Manual Testing Activities</a>          <a href="#slide=52">Lesson 5: Intro Into Automation</a>        </div>      </div>
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1 回答

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TA贡献1810条经验 获得超5个赞

您将该函数添加到标题和按钮 onclick 中,以便它们“同时”运行,因为该按钮是标题的子项并且样式不会更改。


相关代码以及您的问题的一种可能解决方案:


    var button = document.getElementsByClassName('dropbtn')[0];

    ...

    header.onclick = function(event) {

      if (event.target !== button)

        menu.style.display = "none";

    }

测试一下:


var menu = document.getElementsByClassName("dropdown-content")[0];

var header = document.getElementById('header');

var webslidesBody = document.getElementById('webslides');

var button = document.getElementsByClassName('dropbtn')[0];


function lessonSelectionFunction() {

  if (menu.style.display === "none") {

    menu.style.display = "block";

  } else {

    menu.style.display = "none";

  }

}


webslidesBody.onclick = function() {

  menu.style.display = "none";

}


header.onclick = function(event) {

  if (event.target !== button)

    menu.style.display = "none";

}

<header id="header">

  <nav role="navigation" class="nav">

    <div class="dropdown">

      <button class="dropbtn" style="text-transform: none;" onclick="lessonSelectionFunction()">Lesson Selection</button>

      <div class="dropdown-content" style="display:none;">

        <a href="#slide=1">Introduction</a>

        <a href="#slide=4">Lesson 1: Methodologies and Development Lifecycle</a>

        <a href="#slide=18">Lesson 2: IT Support</a>

        <a href="#slide=29">Lesson 3: Testing Foundations</a>

        <a href="#slide=42">Lesson 4: Manual Testing Activities</a>

        <a href="#slide=52">Lesson 5: Intro Into Automation</a>

      </div>

    </div>

  </nav>


  <a id="logout" href="logout.php">Logout</a>

</header>


<article id="webslides">


  <!-- First slide -->

  <section class="slideInRight" id="slide=1">

    // REST OF HTML CONTENT ............

  </section>

</article>


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反对 回复 2023-09-18
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