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TA贡献2021条经验 获得超8个赞
这是一个基本示例。你应该使用FormData
var formData = new FormData();
var uploadFiles = document.getElementById('js-upload-files').files;
this.formData.append("MyKey", uploadFiles[0]);
$.ajax({
type: "POST",
url: 'Controller/Upload',
data: formData,
dataType: 'json',
contentType: false,
processData: false,
complete: this.onComplete.bind(this)
});
编辑
忘记控制器代码
[HttpPost]
public virtual BetterJsonResult Upload()
{
foreach (var fileKey in Request.Files)
{
...Request.Files[fileKey.ToString()] //access it like this
}
}
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