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TA贡献1805条经验 获得超10个赞
考虑以下两个演示。当您有多个观察者时,这些行为会有所不同。在第一个演示中,观察者将竞争队列中的项目,在第二个演示中,他们每个人都会收到一个副本。
演示 #1 - 冷可观察
var queue = new AsyncProducerConsumerQueue<int>();
// This is a cold observable, so each observer is fed by its own individual dequeue loop
// and therefore will be 'competing' with other observers for queued items.
var coldObservable = Observable
// Create an observable that asynchronously waits for items to become available on the
// queue and then emits them to the observer. This will be cancelled when the observer
// is unsubscribed.
.Create<int>(async (observer, cancellationToken) =>
{
while (true)
{
var item = await queue.DequeueAsync(cancellationToken).ConfigureAwait(false);
Console.WriteLine($"Dequeued {item}");
observer.OnNext(item);
}
})
// If an InvalidOperationException is thrown by the above, continue with
// an empty observable instead of the error. This effectively catches an
// `OnError(InvalidOperationException)` and turns it into an `OnCompleted()`.
.Catch<int, InvalidOperationException>(exn =>
{
Console.WriteLine("Caught InvalidOperation");
return Observable.Empty<int>();
});
Console.WriteLine("TEST COLD");
await queue.EnqueueAsync(1);
Console.WriteLine("Enqueued 1");
Console.WriteLine("Subscribing A");
coldObservable.Subscribe(
item => Console.WriteLine($"A received {item}"),
() => Console.WriteLine("A completed"));
Console.WriteLine("Subscribing B");
coldObservable.Subscribe(
item => Console.WriteLine($"B received {item}"),
() => Console.WriteLine("B completed"));
await queue.EnqueueAsync(2);
Console.WriteLine("Enqueued 2");
await queue.EnqueueAsync(3);
Console.WriteLine("Enqueued 3");
queue.CompleteAdding();
Console.WriteLine("Completed adding");
Console.WriteLine("Waiting...");
await Task.Delay(2000);
Console.WriteLine("DONE");
// TEST COLD
// Enqueued 1
// Subscribing A
// Dequeued 1
// A received 1
// Subscribing B
// Enqueued 2
// Enqueued 3
// Completed adding
// Waiting...
// Dequeued 2
// Dequeued 3
// A received 2
// B received 3
// Caught InvalidOperation
// Caught InvalidOperation
// A completed
// B completed
// DONE
演示 #2 - 热可观察
var queue = new AsyncProducerConsumerQueue<int>();
var coldObservable = // defined same as above
// This is a hot observable, so each observer receives the same items from the queue.
var hotObservable = coldObservable
// Publish the cold observable to create an `IConnectableObservable` that will subscribe
// to the dequeue loop when connected and emit the same items to all observers.
.Publish()
// Automatically connect to the published observable when the first observer subscribes
// and automatically disconnect when the last observer unsubscribes. This means that the
// first observer will receive any items queued before it subscribes, but additional
// observers will only receive items queued after they subscribed.
.RefCount();
Console.WriteLine("TEST HOT");
await queue.EnqueueAsync(1);
Console.WriteLine("Enqueued 1");
Console.WriteLine("Subscribing A");
hotObservable.Subscribe(
item => Console.WriteLine($"A received {item}"),
() => Console.WriteLine("A completed"));
Console.WriteLine("Subscribing B");
hotObservable.Subscribe(
item => Console.WriteLine($"B received {item}"),
() => Console.WriteLine("B completed"));
await queue.EnqueueAsync(2);
Console.WriteLine("Enqueued 2");
await queue.EnqueueAsync(3);
Console.WriteLine("Enqueued 3");
queue.CompleteAdding();
Console.WriteLine("Completed adding");
Console.WriteLine("Waiting...");
await Task.Delay(2000);
Console.WriteLine("DONE");
// TEST HOT
// Enqueued 1
// Subscribing A
// Dequeued 1
// A received 1
// Subscribing B
// Enqueued 2
// Enqueued 3
// Dequeued 2
// Completed adding
// Waiting...
// A received 2
// B received 2
// Dequeued 3
// A received 3
// B received 3
// Caught InvalidOperation
// A completed
// B completed
// DONE
回答你原来的问题:
是否可以在没有包装类的情况下编写它?
是的,请参阅上面的演示。
是否可以防止将多个包装器应用于一个队列时出现错误?
上面演示的方法不会阻止其他方将项目出队(或在队列上执行任何其他操作)。如果您想确保只公开给定队列的单个队列IObservable<T>,请考虑通过创建一个ObservableProducerConsumerQueue<T>在内部创建和管理自己的AsyncProducerConsumerQueue. 您可以公开一个EnqueueAsync仅委托给内部队列的方法,并使用上面演示的可观察量之一将可观察量公开为属性或实现接口IObservable<T>。
我可以让它在第一个订阅上连接,而不是通过直接调用 Connect 吗?如果是这样,这意味着什么?
演示 #2 显示了此行为并描述了其含义。如果您希望能够在连接之前订阅观察者,请跳过调用RefCount并像以前一样使用IConnectableObservable返回的值Publish。
最后,你会怎么做呢?
如上所述,我将封装队列并使用上面演示的方法之一公开IObservable或公开。IConnectableObservable
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