我已经解决这个问题有一段时间了,目前正在尝试将我的 php 脚本转换为 PDO,但在运行 isset() 时 $_POST 总是给我 null。我在 android 中的代码与我的其他脚本一起工作得很好,但是当我将每个项目上的 $_POST 更改为 $_REQUEST 并且链接看起来也不同时,这个代码只能在邮递员中工作。还值得一提的是 onResponse 和 onFailure 不会接收/打印任何消息。邮递员网址http://123.456.7.89/Database/register.php?username=asdfasdf&password=lj4ioidfoislkjsf&email=jalenpauloiudf&tece=true&profilePicPath=aksdfjlakjdsfl&tokenId=as89gwbeg98sd当前网址http://123.456.7.89/Database/register.php脚本<?php$servername = "localhost";$dbUsername = "root";$dbPassword = "password";$dbname = "Database";try { $conn = new PDO("mysql:host=$servername;dbname=$dbname", $dbUsername, $dbPassword); $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $username = $_POST['username']; $password = $_POST['password']; $email = $_POST['email']; $termsOfService = $_POST['termsOfService']; $profilePicPath = $_POST['profilePicPath']; $tokenId = $_POST['tokenId']; $userId = uniqId(); //converting data $termsOfService = $termsOfService ? 'true' : 'false'; //Username check $emailForQuery = "%" . $_POST['email'] . "%"; $userIdForQuery = "%" . $userId . "%"; $usernameCheckQuery = $conn->prepare("SELECT email, userId FROM users WHERE email LIKE ? OR userId LIKE ? LIMIT 1"); $usernameCheckQuery->execute([$emailForQuery, $userIdForQuery]); $usernameCheckQuery->fetch();
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