从字符串中提取信息并转换为列表

Question

我有一个如下所示的字符串：[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)我想提取“X”的值和关联的文本并将其转换为列表。请参阅下面的预期输出：预期输出：['X=250.44','DECEMBER 31,']['X=307.5','respectively. The net decrease in the revenue']['X=49.5','(US$ in millions)']我们如何在 Python 中解决这个问题？我的方法：mylist = []for line in data.split("\n"):    if line.strip():        x_coord = re.findall('^(X=.*)\,$', line)        text = re.findall('^(]\w +)', line)        mylist.append([x_coord, text])我的方法没有发现x_coord和的任何价值text。

Answer 1

re解决方案：

import re

input = [

    "[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,",

    "[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue",

    "[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)",

]

def extract(s):

    match = re.search("(X=\d+(?:\.\d*)?).*?\](.*?)$",s)

    return match.groups()

output = [extract(item) for item in input]

print(output)

输出：

[

    ('X=250.44', 'DECEMBER 31,'),

    ('X=307.5', 'respectively. The net decrease in the revenue'),

    ('X=49.5', '(US$ in millions)'),

]

解释：

• \d... 数字

• \d+...一位或多位数字

• (?:...)...非捕获（“正常”）括号

• \.\d*... 点后跟零个或多个数字

• (?:\.\d*)?...可选（零或一）“小数部分”

• (X=\d+(?:\.\d*)?)...第一组，X=number

• .*?...零个或多个任何字符（非贪婪）

• \]...]符号

• $... 字符串结尾

• \](.*?)$...第二组，]字符串之间和结尾之间的任何内容

Answer 2

尝试这个：

(X=[^,]*)(?:.*])(.*)

import re

source = """[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,

[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue

[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)""".split('\n')

pattern = r"(X=[^,]*)(?:.*])(.*)"

for line in source:

    print(re.search(pattern, line).groups())

输出：

('X=250.44', 'DECEMBER 31,')

('X=307.5', 'respectively. The net decrease in the revenue')

('X=49.5', '(US$ in millions)')

您X=在所有捕获前面，所以我只做了一个捕获组，如果重要的话，请随意添加非捕获组。

Answer 3

使用带有命名组的正则表达式来捕获相关位：

>>> line = "[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,"

>>> m = re.search(r'(?:\(X=)(?P<x_coord>.*?)(?:,.*])(?P<text>.*)$', line)

>>> m.groups()

('250.44', 'DECEMBER 31,')

>>> m['x_coord']

'250.44'

>>> m['text']

'DECEMBER 31,'