如何将Excel表格保存到原始工作簿中？

Question

我有一个这样的函数：def DuplicateEachRow():        import pandas as pd        import pathlib        full_path = str(pathlib.Path().absolute()) + '\\' + new_loc        df = pd.read_excel(full_path, header=None, sheet_name='Sheet3')        print(df)        # duplicate the rows:        dup_df = pd.concat([df, df], ignore_index=True)        # using openpyxl        with pd.ExcelWriter(new_loc) as writer:            dup_df.to_excel(writer)我需要保留相同的功能，但不是将一张纸写入新文件。我需要编辑该特定工作表并将其保存回包含其他工作表的工作簿中。编辑（更多解释）：我的工作簿中有 4 张工作表，只有一张工作表（Sheet3）我需要使用上面的功能，然后将其保存回工作簿。这也不起作用，在保存时指定工作表名称：def DuplicateEachRow():        import pandas as pd        import pathlib        full_path = str(pathlib.Path().absolute()) + '\\' + new_loc        df = pd.read_excel(full_path, header=None, sheet_name='GTL | GWL Disclosures')        print(df)        # duplicate the rows:        dup_df = pd.concat([df, df], ignore_index=True)        # using openpyxl        with pd.ExcelWriter(new_loc) as writer:            dup_df.to_excel(writer, sheet_name='GTL | GWL Disclosures')

Answer 1

要在同一个 Excel 中添加新闻表，您必须以追加模式打开文件。看看下面的代码：

def DuplicateEachRow():

    import pandas as pd

    import pathlib

    full_path = str(pathlib.Path().absolute()) + '\\' + new_loc

    df = pd.read_excel(full_path, header=None, sheet_name='GTL | GWL Disclosures')

    print(df)

    # duplicate the rows:

    # keep the index, so you can sort the rows after

    dup_df = pd.concat([df, df])

    #sort the rows by the index so you have the duplicate one just after the initial one

    dup_df.sort_index(inplace=True)

    # using openpyxl

    #open the file in append mode 

    with pd.ExcelWriter(new_loc, mode='a') as writer:

        #use a new name for the new sheet

        #don't save the header (dataframe columns names) and index (dataframe row names) in the new sheet  

        dup_df.to_excel(writer, sheet_name='Sheet3', header=None, index=None)