1 回答
TA贡献1995条经验 获得超2个赞
尝试下面的代码片段会起作用。
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("input").change(function(){
alert("The text has been changed.");
$("#transferredValue").val(this.value)
});
});
</script>
</head>
<body>
<input type="text">
<p></p>
</body>
</html>
Another Way you could try:
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("#valueInput").on('change', function(){
var changeValue = $("#valueInput").val();
alert(changeValue);
});
});
</script>
</head>
<body>
<input type="text" id="valueInput" />
<p></p>
</body>
</html>
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