ES6 中如果包含在字符串中则返回 True

Question

true如果location.pathname在 ES6 中找到这些字符串，我如何返回？  const noActionMenuRoutes = [    '/master/employees',    '/employees/dashboard',    '/employees/requests',    '/projects/myprojects',  ];  const noActionMenus = () => {    if (location.pathname.some(noActionMenuRoutes)) {      return true;    } else {      return false;    }  };

Answer 1

使用查找索引

return noActionMenuRoutes.findIndex(el => el.includes(location.pathname)) != -1;

Answer 2

您可以使用 Javascript 数组includes或indexOf函数。

if (noActionMenuRoutes.some(route => location.pathname.includes(route)))

if (noActionMenuRoutes.some(route => location.pathname.indexOf(route) !== -1)

Answer 3

您可以用来string.includes()确定一个字符串是否可以在另一个字符串中找到。

正如noActionMenuRoutes数组一样，对其进行迭代并针对每个字符串进行验证

const noActionMenus = () => {
    return noActionMenuRoutes.some(x => location.pathname.includes(x))
};

Answer 4

const noActionMenuRoutes = [

    '/master/employees',

    '/employees/dashboard',

    '/employees/requests',

    '/projects/myprojects',

  ];

const noActionMenus = () => noActionMenuRoutes.some(path => location.pathname.includes(path));

console.log(noActionMenus() )