删除日志文件中超过 10 天的所有行

Question

我有一个文件夹，我正在尝试删除所有超过 10 天的行。输入如下：error.log20200122024227-vision.log20200122024730-vision 20200122024930 Missing 20200122024730-vision.log20200520210139 Failed :20200811152053-ibm 20200811152254 Missing20200812164636-ibm_global 20200812164837 Missing20200812210311-ibm_global 20200812210512 Missing20200813080856-ivr 20200813081056 Missing20200813092556-chat_global 20200813092757 Missing20200813125528-ibm_global 20200813125728 Missing20200813163610-acaps_global 20200813163810 Missing20200813172428-mvs_global 20200813172629 Missing20200820204216-pos_global 20200820204417 Missing20200910103742-chatbot_global 20200826103943 Missing20200913103742-chatbot_global 20200826103943 Missing20200914103742-chatbot_global 20200826103943 Missing20200915103742-chatbot_global 20200826103943 Missing20200916103742-chatbot_global 20200826103943 Missing我的输出应该是：20200910103742-chatbot_global 20200826103943 Missing20200913103742-chatbot_global 20200826103943 Missing20200914103742-chatbot_global 20200826103943 Missing20200915103742-chatbot_global 20200826103943 Missing20200916103742-chatbot_global 20200826103943 Missing这些日志不到 10 天。首先，我需要从 is 行获取时间戳20200916103742，并检查它是否小于保留期。如果它被保留，我们必须保留，否则删除。我传递给程序的参数是当前时间戳，保留期为 10 天。所以这意味着我只需要最近 10 天的日志，然后从 error.log 中删除代码如下：current_date = sys.argv[1]retention_period  = sys.argv[2]old_date = int(current_date ) - int(redention_period*1000000)path = "abc/log/log_test/"error_file = path+"error.log"file = open(error_file)output = []for line in file:    print(line)    str_log_key = line[0:13]    log_key = int(str_log_key)    if log_key in range(old_date, current_date):        output.append(line)f.close()f = open(error_file, 'w')f.writelines(output)f.close()我收到如下错误：if log_key in range(old_date, current_date):  TypeError: 'str' object cannot be interpreted as an integer还有其他更好的编码方式吗？

Answer 1

这个功能可能会帮助你：

from datetime import date, timedelta

def del_old():

    limit = "".join(str(date.today() - timedelta(days = 10)).split("-"))

    with open("error.log", "r") as file: 

        data = file.readlines()

    with open("error.log", "w") as file2: 

        for line in data: 

            (int(line.lstrip()[:8]) > int(limit)) and file2.write(line)

Answer 2

假设present_date您的意思是current_date那么您也需要将其转换为整数。

Answer 3

另一种方法是创建一个新文件：

from datetime import date

errorfile = open(f'error.log', 'r')

errorNew = open(f'error_new.log', 'a+')

current_date = date.today()

for line in errorfile:

    date_line = date(int(line[0:4]), int(line[4:6]), int(line[6:8]))

    diff = (current_date - date_line)

    if diff.days < 10:

        errorNew.write(line)