3 回答

TA贡献1835条经验 获得超7个赞
您正在发送 GET 请求,但想要从 POST 获取数据。通过邮寄发送数据
$.post('sendEmail.php', {'name':name,'email':email,'phone':phone,'comments':comments}, function(data){
if (data.indexOf("Message sent") > 0) {
alert("Your email has been sent.");
$('#user-name' + id).val("");
$('#user-phone' + id).val("");
$('#user-email' + id).val("");
$('#user-message' + id).val("");
} else {
alert("Your email could not be sent!")
console.log(data);
}
})

TA贡献1818条经验 获得超8个赞
var parameter = {
name: name,
email:email,
phone: phone,
comments: comments
};
$.ajax({
url: "sendEmail.php",
data:parameter,
method:"POST",
async:true,
success: function(data) {
if (data.indexOf("Message sent") > 0) {
alert("Your email has been sent.");
$('#user-name' + id).val("");
$('#user-phone' + id).val("");
$('#user-email' + id).val("");
$('#user-message' + id).val("");
} else {
alert("Your email could not be sent!")
console.log(data);
}
},
error: function(jqXHR, textStatus, errorThrown) {
alert(textStatus + " - " + errorThrown);
alert(jqXHR.status);
console.log(data);
}
});
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