我尝试使用此对象数组对对象数据进行分组：var data = [ { IdUser: 8, Name: "John Smith", transferType: 'download', total: 6 }, { IdUser: 12, Name: "Jane Smith", transferType: 'download', total: 15 }, { IdUser: 11, Name: "Joe Smith", transferType: 'download', total: 20 }, { IdUser: 12, Name: "Jane Smith", transferType: 'upload', total: 7 }, { IdUser: 11, Name: "Joe Smith", transferType: 'upload', total: 16 }, { IdUser: 8, Name: "John Smith", transferType: 'upload', total: 12 } ];将所有对象的所需输出格式获取到新数组中： [ { IdUser: 8, Name: 'John Smith', download: [{ IdUser: 8, Name: "John Smith", transferType: 'download', total: 6}], upload: [{ IdUser: 8, Name: "John Smith", transferType: 'upload', total: 12 }] }, { IdUser: 12, Name: 'Jane Smith', donwload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'download', total: 15 }], upload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'upload', total: 7 }] }, { IdUser: 11, Name: 'Joe Smith', download: [{ IdUser: 11, Name: "Joe Smith", transferType: 'download', total: 20 }], upload: [{ IdUser: 11, Name: "Joe Smith", transferType: 'upload', total: 16 }] } ];我尝试使用reduce函数，但它不是我得到的所需格式：data.reduce(function (a, b) { a[b.Name] = a[b.Name] || []; a[b.Name]["IdUser"] = b.IdUser; a[b.Name][b.transferType] = a[b.Name][b.transferType] || []; a[b.Name][b.transferType].push(b); return a; }, []);
4 回答
qq_花开花谢_0
TA贡献1835条经验 获得超7个赞
我建议你分两次做。
第一次使用分组功能按 IdUser 对数据进行分组。
然后使用 for in 循环：
var data = [
{
"IdUser": 8,
"Name": "John Smith",
"transferType": "download",
"total": 6
},
{
"IdUser": 12,
"Name": "Jane Smith",
"transferType": "download",
"total": 15
},
{
"IdUser": 11,
"Name": "Joe Smith",
"transferType": "downloaded",
"total": 20
},
{
"IdUser": 12,
"Name": "Jane Smith",
"transferType": "upload",
"total": 7
},
{
"IdUser": 11,
"Name": "Joe Smith",
"transferType": "upload",
"total": 16
},
{
"IdUser": 8,
"Name": "John Smith",
"transferType": "upload",
"total": 12
}
];
var groupBy = function(xs, key) {
return xs.reduce(function(rv, x) {
(rv[x[key]] = rv[x[key]] || []).push(x);
return rv;
}, {});
};
var tmp = groupBy(data, 'IdUser');
var formattedData = [];
for(var id in tmp ){
formattedData.push({
"IdUser": id,
"Name": tmp[id][0].Name,
"download": tmp[id].filter(obj => obj.transferType == "download"),
"upload":tmp[id].filter(obj => obj.transferType == "upload")
})
}
console.log(formattedData)
长风秋雁
TA贡献1757条经验 获得超7个赞
编辑以使用reduce。
var data = [{
IdUser: 8,
Name: "John Smith",
transferType: 'download',
total: 6
},
{
IdUser: 12,
Name: "Jane Smith",
transferType: 'download',
total: 15
},
{
IdUser: 11,
Name: "Joe Smith",
transferType: 'download',
total: 20
},
{
IdUser: 12,
Name: "Jane Smith",
transferType: 'upload',
total: 7
},
{
IdUser: 11,
Name: "Joe Smith",
transferType: 'upload',
total: 16
},
{
IdUser: 8,
Name: "John Smith",
transferType: 'upload',
total: 12
}
];
let ret = data.reduce((ret, cur) => {
let computed = ret.find(record => cur.IdUser === record.IdUser)
if (computed) {
computed[cur.transferType].push(cur)
} else {
let fresh = {
IdUser: cur.IdUser,
Name: cur.Name,
download: [],
upload: []
}
fresh[cur.transferType].push(cur)
ret.push(fresh)
}
return ret
}, [])
console.log(ret)
至尊宝的传说
TA贡献1789条经验 获得超10个赞
您可以使用该array.map方法。
const myObj = [
{
IdUser: 8,
Name: 'John Smith',
download: [{ IdUser: 8, Name: "John Smith", transferType: 'download', total: 6}],
upload: [{ IdUser: 8, Name: "John Smith", transferType: 'upload', total: 12 }]
},
{
IdUser: 12,
Name: 'Jane Smith',
donwload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'download', total: 15 }],
upload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'upload', total: 7 }]
},
{
IdUser: 11,
Name: 'Joe Smith',
download: [{ IdUser: 11, Name: "Joe Smith", transferType: 'downloaded', total: 20 }],
upload: [{ IdUser: 11, Name: "Joe Smith", transferType: 'upload', total: 16 }]
}
];
const uploadData = myObject.map(val => val.upload);
const downloadData = myObject.map(val => val.download);
const newData = uploadData.concat(downloadData);
慕丝7291255
TA贡献1859条经验 获得超6个赞
您可以使用一个简单的循环，例如：
for (let i=0; i<data.length; i++) { ... }在循环内部，您可以访问每个对象和属性，例如：
data[i].IdUser
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