如何使 time.getSeconds() 从 60 到 0 而不是 0 到 60

Question

是否可以制作 time.getSeconds(); 向下而不是向上？var time = new Date();var time2 = time.getSeconds();console.log(time2)

Answer 1

你可以这样做：

var secondsInMinute = 60;

var time = new Date();

var time2 = secondsInMinute - time.getSeconds();

console.log(time2)

Answer 2

Ciao，您可以将自己的函数添加到 Date 原型（称为getMySeconds）以反向方式获取秒数，如下所示：

Date.prototype.getMySeconds = function () {

  return (60 - this.getSeconds());

}

var time = new Date();

var time2 = time.getMySeconds();

console.log(time2)

Answer 3

var time = new Date();

var time2 = time.getSeconds();

const output = 60 - time2;

console.log(output)