一家油漆公司确定,每 115 平方英尺的墙面空间需要一加仑油漆和八小时的劳动力。该公司每小时人工费为 18.00 美元。编写一个程序,允许用户输入要粉刷的房间数量以及每加仑油漆的价格。它还应该询问每个房间的墙壁空间的平方英尺。该程序应具有返回以下数据的方法: • 所需油漆的加仑数 • 所需的人工时间 • 油漆成本 • 人工费用 • 油漆工作的总成本 然后应显示以下数据:屏幕。我还没有解决这个问题的劳动部分,但由于 PaintNeeded 变量,我无法打印 costOfPaint() 。我尝试将 costOfPaint 方法中的语句写入到 main 方法中,并且它有效。但这并没有帮助,因为我需要方法来做到这一点。我知道我的问题与 PaintNeeded 变量有关,我只是不确定如何解决这个问题。公共类主要{public static double paintRequired(double totalSquareFeet){ double paintNeeded = totalSquareFeet / 115; return paintNeeded; }public static double costOfPaint(double paintNeeded, double costOfPaint){ double paintCost = paintNeeded * costOfPaint; return paintCost; }public static void main(String[] args){ double costOfPaint = 0; int totalSquareFeet = 0; double paintNeeded = 0; Scanner getUserInput = new Scanner(System.in); System.out.println("what is the cost of the paint per gallon"); costOfPaint = getUserInput.nextDouble(); System.out.println("How many rooms do you need painted"); int rooms = getUserInput.nextInt(); for(int i = 1; i <= rooms; i++){ System.out.println("how many square feet are in room:" + i); int roomSquareFeet = getUserInput.nextInt(); totalSquareFeet = roomSquareFeet + totalSquareFeet; } System.out.println("the amount of paint needed:" + paintRequired(totalSquareFeet) + "gallons"); System.out.println("the cost of the paint will be: " + costOfPaint(paintNeeded, costOfPaint));}}对于我的绘制成本,我一直得到 0。
1 回答
偶然的你
TA贡献1841条经验 获得超3个赞
你不改变paintNeeded
。总是如此0
。
paintNeeded = paintRequired(totalSquareFeet); System.out.println("the amount of paint needed: " + paintNeeded + " gallons"); System.out.println("the cost of the paint will be: " + costOfPaint(paintNeeded, costOfPaint));
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