从我的 df 开始,我想按如下方式删除行:每次ID检查是否至少一次COD1=COD2且 ifGRADE包含字符串'A'or 'C'。如果满足这两个条件,则删除行。我的想法是这样提出我的条件:indexNames = df[ (df[df.COD1 == df.COD2]) & (df[df['Grade'].isin(['A','C'])]) ].index然后用df.drop(indexNames , inplace=True)然而对于第一行我得到了TypeError: unsupported operand type(s) for &: 'int' and 'float'。我真的很感激任何关于如何实现我的目标的想法。我的 DF:# -- create a dataframe list_columns = ['ID', 'COD1', 'COD2','Grade','Data']list_data = [ [3215575, 'A21', 'A21','A','2020-09-16 13:25:00'], [3215575, 'A11', 'A21','D','2020-09-16 13:55:00'], [3215575, 'A21', 'A21','E','2020-09-16 13:12:00'], [4058770, 'D10', '213','E','2020-09-16 12:25:00'], [4058770, '313', '313','E','2020-09-16 10:25:00'], [4058770, '313', '125','B','2020-09-16 13:19:00'], [4058771, 'C55', 'C55','C','2020-09-16 14:25:00'], [3215577, 'A21', 'A21','B','2020-09-16 13:25:00'], [3215577, 'A01', 'A21','D','2020-09-16 13:55:00'] ]df = pd.DataFrame(columns=list_columns, data=list_data)预期输出: list_columns = ['ID', 'COD1', 'COD2','Grade','Data'] list_data = [ [4058770, 'D10', '213','E','2020-09-16 12:25:00'], [4058770, '313', '313','E','2020-09-16 10:25:00'], [3215577, 'A21', 'A21','B','2020-09-16 13:25:00'], [3215577, 'A01', 'A21','D','2020-09-16 13:55:00'] ]df2 = pd.DataFrame(columns=list_columns, data=list_data)
1 回答
![?](http://img1.sycdn.imooc.com/545868190001d52602200220-100-100.jpg)
慕桂英4014372
TA贡献1871条经验 获得超13个赞
IIUC,,你需要一个条件,用 groupby 并用 any 进行变换,然后反转:
cond = (df.COD1 == df.COD2) & df['Grade'].isin(['A','C'])
df2 = df[~cond.groupby(df['ID']).transform('any')].reset_index(drop=True)
ID COD1 COD2 Grade Data
0 4058770 D10 213 E 2020-09-16 12:25:00
1 4058770 313 313 E 2020-09-16 10:25:00
2 4058770 313 125 B 2020-09-16 13:19:00
3 3215577 A21 A21 B 2020-09-16 13:25:00
4 3215577 A01 A21 D 2020-09-16 13:55:00
添加回答
举报
0/150
提交
取消