Python URL 编码问题

Question

我正在尝试修改 ANKI 插件 .py 文件，以便能够解析牛津的单词from urllib.parse import urlencodeqs = urlencode({"q": "come along"})URL = "https://www.oxfordlearnersdictionaries.com/search/english/?{}"print(URL.format(qs))我的输出“https://www.oxfordlearnersdictionaries.com/search/english/?q=come+along”但实际上输出应该是这样的“https://www.oxfordlearnersdictionaries.com/definition/english/come-along?q=come+along”我怎样才能克服这个问题我是初学者#-- coding:utf-8 --import randomfrom ..base import *import requestsfrom bs4 import BeautifulSoupfrom time import sleepfrom random import randint@register(u'Oxford_Article')class Oxford_Article(WebService):    def init(self):        super(Oxford_Article, self).init()    def _get_from_api(self):        sleep(randint(1,3))                param = {"q": "come along"}        qs = urlencode(param)        param['q'] = param['q'].replace(' ', '-')        URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"                data = self.get_response(URL.format(param['q'],qs))        soup = parse_html(data)        result = {            'Article': u'',        }        # Article        element = soup.find('div', id='entryContent')        for s in element.select('script'):            s.extract()        if element:            result['Article'] = u''.join(str(e) for e in element.contents)        return self.cache_this(result)    @export([u'entryContent', u'Article definition'])    def fld_definate(self):        return self._get_field('Article')

Answer 1

你可以这样做

from urllib.parse import urlencode

param = {"q": "come along"}

qs = urlencode(param)

param['q'] = param['q'].replace(' ', '-')

URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"

print(URL.format(param['q'],qs))

Answer 2

如果您在解析数据时遇到错误

只需替换这段代码

data = self.get_response(URL.format(param['q'],qs))
soup = parse_html(data)

用这个代码

page = urllib.request.urlopen(URL.format(param['q'],qs))
soup = BeautifulSoup(page)

也不要忘记导入这个

import urllib.request