我试图制作一个改进的自动答题器,具有更多功能,例如:按一个键保存光标位置按键时执行按一下键杀死程序这是代码:import win32api, win32comimport pyautoguiimport tkinter as tkfrom time import sleepimport keyboardwin = tk.Tk()cursor = (0,0)di = 0e = tk.Entry()def geti(): di = float(e.get())l = tk.Label(text="Info:").pack()l1 = tk.Label(text="Press q to stop clicking").pack()l2 = tk.Label(text="Press c to copy mouse position to execute on").pack()l3 = tk.Label(text="Press e to start executing").pack()dl = tk.Label(text="Delay between eack click (s)").pack()e.pack()b = tk.Button(text="save delay time",command=geti).pack()def click(x, y): win32api.SetCursorPos((x,y)) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN,0,0) sleep(di) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP,0,0)while True: if(keyboard.is_pressed('c') == True): cursor = pyautogui.position() if(keyboard.is_pressed('q') == True): break if(keyboard.is_pressed('e') == True): click(cursor[0], cursor[1]) win.mainloop()
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精慕HU
TA贡献1845条经验 获得超8个赞
你的 while 循环会阻塞 win.mainloop()。您可以使用带有绑定的 tkinters 事件系统,而不是检查按键:
win.bind('key', callback)
# thanks to @acw1668's comment: added evt
win.bind('e', lambda evt: click(cursor[0], cursor[1]))
lambda 是必要的,因为您希望调用函数而不是结果。来自tkinter 文档:
如果这样做,Python 将在创建小部件之前调用回调函数,并将函数的返回值传递给 Tkinter。然后,Tkinter 尝试将返回值转换为字符串,并告诉 Tk 在激活按钮时调用具有该名称的函数。这可能不是您想要的。
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