如何在另一个按钮调用的函数中检测到 gpiozero 按钮按下？

Question

我需要通过按下按钮触发继电器并等待信号然后释放继电器。在下面的示例代码中，该信号是 b2。我是 Python 和 Pi 的新手，但玩得很开心！:)import RPi.GPIO as GPIOGPIO.setmode(GPIO.BCM)from gpiozero import Buttonfrom signal import pauseimport timedef first_button():    print("First Pressed")    while True: #do stuff...        time.sleep(1)        print("waiting...")def second_button():    print("Second Pressed")b1 = Button(23)b1.when_pressed = first_buttonb2 = Button(24)b2.when_pressed = second_buttonpause()当按钮调用的现有函数仍在运行时，如何检测按钮按下情况？

Answer 1

在此解决方案中，您只需打开和关闭输出

from gpiozero import Button

from signal import pause

import time

pin = #Set a pin

r = LED(pin)

b1 = Button(23)

b1.when_pressed = r.on

b2 = Button(24)

b2.when_pressed = r.off

pause()

这里启动一个线程来做一些事情：

from gpiozero import Button

from signal import pause

import time

import _thread

run = False

def do_stuff():

    while run: #do stuff...

        time.sleep(1)

        print("waiting...")

def first_button():

    global run

    print("First Pressed")

    run = True

    _thread.start_new_thread(do_stuff)

    

def second_button():

    global run

    print("Second Pressed")

    run = False

b1 = Button(23)

b1.when_pressed = first_button

b2 = Button(24)

b2.when_pressed = second_button

pause()